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4 years ago

Max bought some tins and decided to fill them with brownies to give to his friends. Max baked

Mathematics

1 answer:

vredina [299]4 years ago

7 0

Answer: 7

Step-by-step explanation:

Assuming he didn't put the brownies in a spare tin, you would just have to divide 495 by 8 and the remainder would be the answer.

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Please please help me omg I give 28 points

Semmy [17]

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3 years ago

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What is the length of WY if XZ=6

olga_2 [115]

Answer:

WY= squar root 55 + 4

Step-by-step explanation:

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3 years ago

Zipora wants to construct a triangle that has the following angle measures: 50°, 75°, and 55°. How many triangles can she make?

Alborosie

As sum of all angles of triangle equal to 180 degrees.
First we have to add the angles.
50+75+55
=50+130
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Answer: Zipora can construct exactly one triangle.

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3 years ago

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1. find the balance after one year if you deposit all the money into an account that pays $2.50 in simple interest each month (t

Naddika [18.5K]

1. Balance after 1 year with simple interest= 600 + (2.5 x 12) = 600 + 30 = $630

2. Balance after 1 year with compounded interest = P ( 1 + $\frac{r}{n}$ $)^{nt}$

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6 0

4 years ago

A square napkin is folded in half on the diagonal and placed on the diameter of a round plate (see diagram below). If the folded

Crank

Answer:

$A=81(\pi-1)\ in^2$

Step-by-step explanation:

step 1

Find the area of the plate

The area of a circle is given by the formula

$A=\pi r^{2}$

we have

$r=18/2=9\ in$ ---> the radius is half the diameter

substitute

$A=\pi (9)^{2}\\A=81\pi\ in^2$

step 2

Find the area of the square napkin folded (is a half of the area of the square napkin)

we know that

The diagonal of the square is the same that the diameter of the plate

Applying Pythagorean theorem

$D^2=2b^2$

where

b is the length side of the square

we have

$D=18\ in$

substitute

$18^2=2b^2$

solve for b^2

$b^2=162\ in^2$ -----> is the area of the square

Divide by 2

$162/2=81\ in^2$

step 3

Find the area of the space on the plate that is NOT covered by the napkin

we know that

The area of the space on the plate that is NOT covered by the napkin, is equal to subtract the area of the square napkin folded (is a half of the area of the square napkin) from the area of the plate

$A=(81\pi-81)\ in^2$

simplify

$A=81(\pi-1)\ in^2$

8 0

3 years ago