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2 years ago

PLEASE FIX THIS LUA SCRIPT

Engineering

2 answers:

yKpoI14uk [10]2 years ago

6 0

Answer: not sure

Explanation: brainly please

zavuch27 [327]2 years ago

5 0

Answer:

When declaring variables, you said “workspace.MeanEnemy”. What you should have done was “game.Workspace.MeanEnemy”. Same for the variable right under it. Other than that, seems to be all good!

Hope This Helped!

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You have discovered an element that is a poor conductor of electricity, has a low melting point, and is a gas at room temperatur

Scorpion4ik [409]

Answer:

All nonmetallic elements are generally poor conductors of heat and electricity. There are only 17 nonmetallic elements, while more than 75 percent of the known elements are either pure metals or metalloids, which are better conductors of heat and electricity to a varying degree.

Explanation:

3 0

3 years ago

An oscillating mechanism has a maximum displacement of 3.2m and a frequency of 50Hz. At timet-0 the displacement is 150cm. Expre

Helen [10]

Given:

max displacement, A = 3.2 m

f= 50 Hz

at t = 0, displacement, d = 150 cm = 1.5 m

Solution:

Displacement in the general form is represented by:

d = Asin(ωt ± α)

d = 3.2sin(2πft ± α)

d = 3.2sin(100πt ± α)

where,

A = 3.2 m,

ω = 2πf = 100π

Now,

at t = 0,

1.5 = 3.2sin(100π(0) ± α )

1.5 = 3.2sinα

sin α = $\frac{1.5}{3.2}$ = 0.4687

α = $sin^{-1}(0.46875)$ = 27.95° = 0.488 radian

Now, we can express displacement in the form of 'Asin(wt + α)' as:

d = 3.2sin(100πt ± 0.488 )

6 0

3 years ago

Where do the names of counterweight items originally come from

Ugo [173]

Answer:

an equivalent weight or force : counterbalance.

4 0

3 years ago

Read 2 more answers

A strain gauge with a 4 mm gauge length gives a displacement reading of 1.5 um. Calculate the stress at the location of the stra

Art [367]

Answer:

1) 75Mpa

2) 1.125 MPa

Explanation:

given data:

gauge length = 4 mm

displacement $= 1.5\mu m = 1.5\times 10^{-3} m$

a) structural steel

Young modulus for steel is $200 GPa = 200\times 10^3 MPa$

we know that

$E =\frac{stress}{strain}$

$Stress = 200\times 10^3 \times \frac{1.5\times 10^{-3}}{4}$

= 75Mpa

b) PMMA

Young's modulus $= 3GPa = 3\times10^3 MPa$

$stress = 3\times \frac{1.5\times10^{-3}}{4}$

stress = 1.125 MPa

3 0

3 years ago

Consider steady heat transfer through the wall of a room in winter. The convection heat transfer coefficient at the outer surfac

AveGali [126]

The heat transfer which is in steady state, the heat transfer rate to the wall is equal to the wall.

<u>Explanation:</u>

The convection transfer of heat to the wall is

$Q=h A\left(T_{s}-T_{f}\right)$

Here, $T_{S}$ is the temperature of solid surface, $T_{f}$ is the temperature of moving fluid stream which is adjacent of solid surface, h is the heat transfer coefficient.
The coefficient of convection heat transfers outer surface contains 3 times to the inner surface which experience smaller drop of temperature for 3 times that compares to inner surface.
Hence, the temperatures outer surface get close to the surroundings of air temperature.

6 0

3 years ago