Answer:
Detailed solution is attached below in three simple steps the problem is solved.
Answer:
The level of the service is loss and the density is 34.2248 pc/mi/ln
Explanation:
the solution is attached in the Word file
Answer:
A) 30 mH
B ) 10-ohm
Explanation:
resistor = 10-ohm
Inductor = 30mH ( l )
L = inductance
R = resistance
r = internal resistance
values of the original Inductors
Note : inductor = constant time (t) case 1
inductor + 10-ohm resistor connected in series = constant time ( t/2) case2
inductor + 10-ohm resistor + 30 mH inductance in series = constant time (t) case3
<em>From the above cases</em>
case 1 = time constant ( t ) = L / R
case 2 = Req = R + r hence time constant t / 2 = L / R + r therefore
t = 
case 3 = Leq = L + l , Req = R + r . constant time ( t )
hence Z =
= t
A) Inductance
To calculate inductance equate case 1 to case 3
=
= L / 10 = (L + 30) / ( 10 + 10 )
= 20 L = 10 L + 300 mH
10L = 300 m H
therefore L = 30 mH
B ) The internal resistance
equate case 1 to case 2
= 
R + r = 2 R therefore ( r = R ) therefore internal resistance = 10-ohm
Explanation:
a). <u>Operational Performance</u>
It is defined as the parameter that describes the percentage of accuracy of performing an operation or carrying out an activity.
b). <u>Salvage externalities</u>
Salvage in Life cycle cost analysis is a process of estimating the value of the remaining assets in the organisation,.
c). <u>Value Vs Risk</u>
When we take risk in doing any activity we know the value of accomplising the activity. So value relates directly with risk. When the value of a certain task is high, the risk involve in it is also high.
d). <u>Initial expenditure</u>
Initial expenditure is nothing but the cost involve in starting a particular acitvity or task at the starting phase.
e). <u>Maintenance implications</u>
It lays emphasis in maintaining the cost of every possible parameters that are involve in the activity. It includes labour, machines, positions, energy, facilities, etc.
Answer:
"""""""""""""""""""""""""In case of any doubt please comment""""""""""""""""""""""""
Now we need the function to return true if noTraffic= true and gasEmpty = false;
NOTE:"Rest in all cases it should return false;
Now for that to happen we use and- operator (x & y) it returns true only when both x and y are true.
but we need true when gasEmpty = false. For that we will use not function on gasEmpty.
Now the function will return true (1) only when noTraffic = true and gasEmpty = false. Rest in all case it will return false (0)
function onTime = RunningLate (noTraffic, gasEmpty)
onTime = ( (noTraffic) & not(gasEmpty) )
end