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amm1812
3 years ago
8

A satellite at a distance of 36,000 km from an earth station radiates a power of 10 W from an

Engineering
1 answer:
notsponge [240]3 years ago
4 0
This an example solved please follow up with they photo I sent ok

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Find the toughness (or energy to cause fracture) for a metal that experiences both elastic and plastic deformation. Assume Equat
PtichkaEL [24]

Answer:

Detailed solution is attached below in three simple steps the problem is solved.

7 0
3 years ago
A westbound section of freeway currently has three 12-ft wide lanes, a 6-ft right shoulder, and no ramps within 3 miles upstream
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The level of the service is loss and the density is 34.2248 pc/mi/ln

Explanation:

the solution is attached in the Word file

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6 0
3 years ago
An inductor is connected to a voltage source and it is found that it has a time constant, t. When a 10-ohm resistor is placed in
prisoha [69]

Answer:

A) 30 mH

B ) 10-ohm

Explanation:

resistor = 10-ohm

Inductor = 30mH ( l )

L = inductance

R = resistance

r = internal resistance

values of the original Inductors

Note : inductor = constant time (t)  case 1

inductor + 10-ohm resistor connected in series = constant time ( t/2) case2

inductor + 10-ohm resistor + 30 mH inductance in series = constant time (t) case3

<em>From the above cases</em>

case 1 = time constant ( t ) = L / R

case 2 = Req = R + r hence time constant  t / 2  = L / R + r  therefore

t = \frac{2L}{R+r}

case 3 = Leq = L + l , Req = R + r .  constant time ( t )

hence Z = \frac{L + l}{R + r} = t

A) Inductance

To calculate inductance equate case 1 to case 3

\frac{L}{R} = \frac{L + l}{R + r} =   L / 10 = (L + 30) / ( 10 + 10 )

= 20 L = 10 L + 300 mH

   10L = 300 m H

therefore L = 30 mH

B ) The internal resistance

equate case 1 to case 2

\frac{L}{R} = \frac{2L}{R + r}

R + r = 2 R  therefore  ( r = R )   therefore internal resistance = 10-ohm

6 0
3 years ago
Describe the steps involved in accomplishing a life-cycle cost analysis (LCCA). I have listed the steps. just describe. a)-Opera
Tasya [4]

Explanation:

a). <u>Operational Performance</u>

     It is defined as the parameter that describes the percentage of accuracy of performing an operation or carrying out an activity.

b).  <u>Salvage externalities</u>

   Salvage in Life cycle cost analysis is a process of estimating the value of the remaining assets in the organisation,.

c). <u>Value Vs Risk</u>

   When we take risk in doing any activity we know the value of accomplising the activity. So value relates directly with risk. When the value of a certain task is high, the risk involve in it is also high.

d). <u>Initial expenditure</u>

   Initial expenditure is nothing but the cost involve in starting a particular acitvity or task at the starting phase.

e). <u>Maintenance implications</u>

   It lays emphasis in maintaining the cost of every possible parameters that are involve in the activity. It includes labour, machines, positions, energy, facilities, etc.

8 0
3 years ago
Logical variables: Running late? Complete the tunction RunningLate such that the logical variable on Time is true if no Traffic
MrMuchimi

Answer:

"""""""""""""""""""""""""In case of any doubt please comment""""""""""""""""""""""""

Now we need the function to return true if noTraffic= true and gasEmpty = false;

NOTE:"Rest in all cases it should return false;

Now for that to happen we use and- operator (x & y) it returns true only when both x and y are true.

but we need true when gasEmpty = false. For that we will use not function on gasEmpty.

Now the function will return true (1) only when noTraffic = true and gasEmpty = false. Rest in all case it will return false (0)

​​​​​​​

function onTime = RunningLate (noTraffic, gasEmpty)

onTime = ( (noTraffic) & not(gasEmpty) )

end

8 0
3 years ago
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