Current is the flow of what?
1 answer:
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Refer to the diagram shown below.
The following discussion assumes a simplistic analysis that ignores air resistance and variations in the terrain that the missile travels over.
Let the launch velocity be V₀ at an angle of θ relative to the horizontal.
The horizontal component of velocity is V₀ cosθ.
If the time of flight is
, then
where r = the range of the missile.
Also, the time, t, when the missile is at ground level is given by
where g = acceleration due to gravity.
t = 0 corresponds to when the missile is launched. Therefore
Therefore
Typically, θ=45° to achieve maximum range, so that
This analysis is more applicable to a scud missile rather than a powered, guided missile.
Answer:
Usually, θ=45°
The following discussion assumes a simplistic analysis that ignores air resistance and variations in the terrain that the missile travels over.
Let the launch velocity be V₀ at an angle of θ relative to the horizontal.
The horizontal component of velocity is V₀ cosθ.
If the time of flight is
where r = the range of the missile.
Also, the time, t, when the missile is at ground level is given by
where g = acceleration due to gravity.
t = 0 corresponds to when the missile is launched. Therefore
Therefore
Typically, θ=45° to achieve maximum range, so that
This analysis is more applicable to a scud missile rather than a powered, guided missile.
Answer:
Usually, θ=45°