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torisob [31]
2 years ago
6

Which terms describe the motion of most objects in our solar system?

Physics
2 answers:
olga2289 [7]2 years ago
6 0

Answer:Geography, Earth Science, Astronomy

Rotation describes the circular motion of an object around its center.

Explanation:

Shalnov [3]2 years ago
3 0

Answer:

it is Cyclic and predictable

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if a sea star egg is taken from the ocean and put into Elk Lake would you expect the egg to shrink swell are stay the same ?
mafiozo [28]
It would swell

and be swell
7 0
3 years ago
You attach a 3.10 kg weight to a horizontal spring that is fixed at one end. You pull the weight until the spring is stretched b
dolphi86 [110]

Answer:

0.785 m/s

Explanation:

Hi!

To solve this problem we will use the equation of motion of the harmonic oscillator, <em>i.e.</em>

x(t) = A cos(\omega t )+B sin(\omega t) - (1)

\frac{dx}{dt}(t) = \omega (B cos(\omega t )- A sin(\omega t) - (1)

The problem say us that the spring is released from rest when the spring is stretched by 0.100 m, this condition is given as:

x(0) = 0.100

\frac{dx}{dt}(0) = 0

Since cos(0)=1 and sin(0) = 0:

x(0)=A

\frac{dx}{dt}(0) = -B\omega

We get

A =0.100\\B = 0

Now it say that after 0.4s the weigth reaches zero speed. This will happen when the sping shrinks by 0.100. This condition is written as:

x(0.4) = - 0.100

Since

x(t) = 0.100 cos(\omega t)\\ -0.100=x(0.4)=0.100cos(\omega 0.4)

This is the same as:

-1 = cos(0.4\omega)

We know that cosine equals to -1 when its argument is equal to:

(2n+1)π

With n an integer

The first time should happen when n=0

Therefore:

π = 0.4ω

or

ω = π/0.4  -- (2)

Now, the maximum speed will be reached when the potential energy is zero, <em>i.e. </em>when the sping is not stretched, that is when x = 0

With this info we will know at what time it happens:

0 = x(t) = 0.100cos(\omega t)

The first time that the cosine is equal to zero is when its argument is equal to π/2

<em>i.e.</em>

t_{maxV}=\pi /(2\omega)

And the velocity at that time is:

\frac{dx}{dt}(t_{maxV} ) =- 0.100\omega sin(\omega t_{maxV})\\\frac{dx}{dt}(t_{maxV} ) =- 0.100\omega sin(\pi/2)\\

But sin(π/2) = 1.

Therefore, using eq(2):

\frac{dx}{dt}(t_{maxV} ) = 0.100*\omega = 0.100\frac{\pi}{0.400} = \pi/4

And so:

V_{max} = \pi / 4 =0.785

6 0
2 years ago
An optical disk drive in your computer can spin a disk up to 10,000 rpm (about 1045 rad / s). if a particular disk is spun at 79
NeX [460]
(i) |α| = 235.6rad.s / 0.502s = 469 rad/s²
(ii) tang a = α*r = 469rad/s² * 0.12m / 2*11 = 2.56 m/s²
4 0
3 years ago
3. Using the F, m, a triangle, calculate the boy's mass. Use the "force
aliya0001 [1]

Answer: 30kg

Explanation:

F = 300N

m = ?

a = 10 m/s/s

m = f/a = 300N/10 m/s/s

m = 30kg

5 0
2 years ago
If an astronaut weighs 900 n on earth, what does he weigh on the planet venus?
Ber [7]
Use w=m*g value of g is 1.67m/s^2
5 0
3 years ago
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