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torisob [31]
3 years ago
6

Which terms describe the motion of most objects in our solar system?

Physics
2 answers:
olga2289 [7]3 years ago
6 0

Answer:Geography, Earth Science, Astronomy

Rotation describes the circular motion of an object around its center.

Explanation:

Shalnov [3]3 years ago
3 0

Answer:

it is Cyclic and predictable

You might be interested in
If acceleration is zero what statement about velocity is true *
Wittaler [7]

Answer:

Option"B" is correct.

Explanation:

when a body move with constant velocity then acceleration is zero.

6 0
3 years ago
Read 2 more answers
3. An engine’s fuel is heated to 2,000 K and the surrounding air is 300 K. Calculate the ideal efficiency of the engine. Hint: T
maksim [4K]

Answer: E = 0.85

Therefore the efficiency is: E = 0.85 or 85%

Explanation:

The efficiency (e) of a Carnot engine is defined as the ratio of the work (W) done by the engine to the input heat QH

E = W/QH.

W=QH – QC,

Where Qc is the output heat.

That is,

E=1 - Qc/QH

E =1 - Tc/TH

where Tc for a temperature of the cold reservoir and TH for a temperature of the hot reservoir.

Note: The unit of temperature must be in Kelvin.

Tc = 300K

TH = 2000K

Substituting the values of E, we have;

E = 1 - 300K/2000K

E = 1 - 0.15

E = 0.85

Therefore the efficiency is: E = 0.85 or 85%

4 0
4 years ago
Which is heavier 1kg of iron or 1 kg of feathers?
Tema [17]

-- On Earth, 1 kg of anything weighs 9.81 Newtons (2.205 pounds). It doesn't matter what substance comprises the kilogram.

-- Although their weights are identical, any mass of feathers occupies more volume than the same mass of iron, no matter where they happen to be located.

-- Iron is more dense than feathers, and more dense than a lot of other substances as well, too.

7 0
4 years ago
Global winds are found in each convection region. Because convection cells are in a set place in the atmosphere and the Earth is
Lemur [1.5K]
Coriolis effect that's due to the motion of the Earth
7 0
3 years ago
Read 2 more answers
A boy shoves his stuffed toy zebra down a frictionless chute. It starts at a height of 1.69 m above the bottom of the chute with
Veseljchak [2.6K]

Answer:

x = 6.94 m

Explanation:

For this exercise we can find the speed at the bottom of the ramp using energy conservation

Starting point. Higher

            Em₀ = K + U = ½ m v₀² + m g h

Final point. Lower

            Em_{f} = K = ½ m v²

            Em₀ = Em_{f}

            ½ m v₀² + m g h = ½ m v²

            v² = v₀² + 2 g h

             

Let's calculate

             v = √(1.23² + 2 9.8 1.69)

             v = 5.89 m / s

In the horizontal part we can use the relationship between work and the variation of kinetic energy

            W = ΔK

            -fr x = 0- ½ m v²  

               

Newton's second law

              N- W = 0

     

The equation for the friction is

               fr = μ N

               fr = μ m g

We replace

             μ m g x = ½ m v²

             x = v² / 2μ g

Let's calculate

            x = 5.89² / (2 0.255 9.8)

            x = 6.94 m

6 0
4 years ago
Read 2 more answers
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