Answer:
V₀y = 0 m/s
t = 2.47 s
V₀ₓ = 61.86 m/s
Vₓ = 61.86 m/s
Explanation:
Since, the ball is hit horizontally, there is no vertical component of velocity at initial point. So, the initial vertical velocity (V₀y) will beL
<u>V₀y = 0 m/s</u>
For the initial vertical velocity of golf ball we consider the vertical motion and apply 2nd equation of motion:
Y = V₀y*t + (0.5)gt²
where,
Y = Height = 30 m
g = 9.8 m/s²
t = time to hit the ground = ?
Therefore,
30 m = (0 m/s)(t) + (0.5)(9.8 m/s²)t²
t² = 30 m/4.9 m/s²
t = √6.122 s²
<u>t = 2.47 s</u>
For initial vertical velocity we analyze the horizontal motion of the ball. We neglect the frictional effects in horizontal motion thus the speed remains uniform. Hence,
V₀ₓ = Xt
where,
V₀ₓ = Initial vertical Velocity = ?
X = Horizontal Distance = 25 m
Therefore,
V₀ₓ = (25 m)(2.47 s)
<u>V₀ₓ = 61.86 m/s</u>
<u></u>
Due, to uniform motion in horizontal direction:
Final Vertical Velocity = Vₓ = V₀ₓ
Vₓ = 61.86 m/s
 
        
             
        
        
        
The change in the player's internal energy is -491.6 kJ. The number of nutritional calories is -117.44 kCal 
For this process to take place, some of the basketball player's perspiration must escape from the skin. This is because sweating relies on a physical phenomenon known as the heat of vaporization. 
The heat of vaporization refers to the amount of heat required to convert 1g of a liquid into a vapor without causing the liquid's temperature to increase. 
From the given information, 
- the work done on the basketball is dW = 2.43 × 10⁵ J
The amount of heat loss is represented by dQ.
where;
∴
Using the first law of thermodynamics:b
dU = dQ - dW
dU = -mL - dW
dU = -(0.110 kg × 2.26 × 10⁶ J/kg - 2.43 × 10⁵ J)
dU = -491.6 × 10³ J
dU = -491.6 kJ
The number of nutritional calories the player has converted to work and heat can be determined by using the relation:

dU = -117.44 kcal 
Learn more about first law of thermodynamics here:
brainly.com/question/3808473?referrer=searchResults
 
        
             
        
        
        
Answer:

Explanation:
From the question we are told that 
Nucleus diameter 
a 12C nucleus
Required kinetic energy 
Generally initial speed of proton must be determined,applying the law of conservation of energy we have
             
where 
 =initial kinetic energy
 =initial kinetic energy
 =final kinetic energy
 =final kinetic energy
 =initial electric potential
 =initial electric potential
 =final electric potential
 =final electric potential
mathematically
    
where 
 =distance b/w charges
=distance b/w charges
 =nucleus charge
=nucleus charge 
 =constant
=constant
 =proton charge
=proton charge
 Generally kinetic energy is know as
          
Therefore
           
 
Generally equation for radius is 
Mathematically solving for radius of nucleus 
          
          
Generally we can easily solving mathematically substitute into v_1
    

    
    
    
    
    
    
     
Therefore the proton must be fired out with a speed of 
 
        
             
        
        
        
Answer:
The centripetal acceleration of the child at the bottom of the swing is 15.04 m/s².
                      
Explanation:
The centripetal acceleration is given by:
 
 
Where:
 : is the tangential speed = 9.50 m/s
: is the tangential speed = 9.50 m/s
r: is the distance = 6.00 m
Hence, the centripetal acceleration is:

Therefore, the centripetal acceleration of the child at the bottom of the swing is 15.04 m/s².
I hope it helps you!
 
        
                    
             
        
        
        
Answer:
Sorry don't know the answer