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S_A_V [24]
3 years ago
5

DANIEL HAS A SAMPLE OF PURE COPPER. ITS MASS IS 89.6 GRAMS, AND ITS VOLUME IS 10 CUBIC CENTIMETERS. WHATS THE DENSITY OF THE SAM

PLE

Physics
2 answers:
Vitek1552 [10]3 years ago
6 0
So the formula for density is mass divided by volume, so it would be

olga2289 [7]3 years ago
5 0
8.96 grams/cubic cm
 density= mass/volume
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Substance A has twice the specific heat capacity as substance B. If 1000 J of heat are added to 1.0 kg of each substance, compar
Mrrafil [7]
Substance A would have a delta T (change in temp) rise 1/2 the rise in substance B.

Q=mc x delta T

Q= heat energy in Joules
m= mass of substance heated or cooled
c= specific heat
ΔT is change in temp.

Solve for change in temp=. Q/mc

Specific heat and mass are not inversely proportional to heat energy input.

Putting into real world scenario of using water to heat a building.

Specific heat of water is 1.
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4 0
3 years ago
This chart shows characteristics of three different waves all with the same wavelength of 10 m but moving at different frequenci
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Answer:

the answer is B

Explanation:

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6 0
3 years ago
A 5 cm spring is suspended with a mass of 3.8589 g attached to it which extends the spring by 1.5747 cm. The same spring is plac
lana66690 [7]

Answer:

charges of the beads is 1.173 ×10^{-15} C

Explanation:

given data

mass = 3.8589 g = 0.003859 kg

spring length = 5 cm = 0.05 m

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spring's extension = 0.0116 m

to find out

charges of the beads

solution

we know that force is

force = mass × g

force = 0.003859 × 9.8

force = 0.03782 N

so we know  force for mass

force  = -kx

so k = force / x

put here force and x value

k = -0.03782 / 0.1575

k = -0.24 N/m

and

force for spring's extension

force = -kx

force = -0.24 ( 0.0116) = 0.002784 N

so here

total length L = 0.05 + 0.0116 = 0.0616

so charges of the beads = force × L² / ke

charges of the beads = 0.002784 × (0.0616)² / (9 ×10^{9} )

so charges of the beads = 1.173 ×10^{-15} C

3 0
3 years ago
What is your initial speed if you accelerate at 5.8 m/s/s for 3.0 seconds and achieve a final speed of 45 m/s?
Natali5045456 [20]

Answer:

27.6 m/s

Explanation:

hopefully it makes sense and is visible

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8 0
2 years ago
What is the dimensional formula of young modulas​
LekaFEV [45]

Answer:

The dimensional formula of Young's modulus is [ML^-1T^-2]

6 0
3 years ago
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