Answer:
The speed in scientific notation is
feet per second.
Step-by-step explanation:
1. You have the following speed: One thousand one houndred feet per second.
2. You must convert from words to number. This is:
1,100 feet per second
3. To express this quantity in scientific notation, you can move the decimal point three places to the left, and write it as: 1.1 by
(or 1,000) as following:

Answer:
Read below.
Step-by-step explanation:
The total number of branches end of the tree is the denominator of the fraction form of probability.
All the total possible outcomes in an organized list will give you a denominator because that's all the outcomes that can happen from that set of data.
Answer:
Correct
Step-by-step explanation:
When you type 1/3 into a calculator it should give you something along the lines of .333333334. If you continue to round, eventually you will get 1.
Answer:
Well we add together 20+15 which is 35 which is 5 over the 30 in the class so that means out of the 30 students 5 of them like both games
Hope This Helps
We want to find the probability that the two students chosen for the duet are boys. We will find that the probability that both students chosen for the duet are boys is 0.458
If we assume that the selection is totally random, then all the students have the same<em> </em><em>probability </em><em>of being chosen.</em>
This means that, for the first place in the duet, the probability of randomly selecting a boy is equal to the quotient between the number of boys and the total number of students, this is:
P = 11/16
For the second member of the duet we compute the probability in the same way, but this time there is one student less and one boy less (because one was already selected).
Q = 10/15
The joint probability (so both of these events happen together) is just the product of the individual probabilities, this will give:
Probability = P*Q = (11/16)*(10/15) = 0.458
So the probability that both students chosen for the duet are boys is 0.458
If you want to learn more, you can read:
brainly.com/question/1349408