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Rzqust [24]
3 years ago
9

Rachel bought 2 pounds of apples and 3 pounds of peaches for a total of $20.45. The apples and peaches cost the same amount per

pound. What was the unit rate?
Mathematics
1 answer:
Likurg_2 [28]3 years ago
8 0
Each pound would cost at least 4.09$
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Ship collisions in the Houston Ship Channel are rare. Suppose the number of collisions are Poisson distributed, with a mean of 1
alexandr1967 [171]

Answer:

a) \simeq 0.3012   b) \simeq 0.0494 c) \simeq 0.2438

Step-by-step explanation:

Rate of collision,

1.2 collisions every 4 months

or, \frac{1.2}{4}

= 0.3 collisions per  month

So, the Poisson distribution for the random variable no. of collisions per month (X) is given by,

          P(X =x) = \frac{e^{-\lambda}\times {\lambda}^{x}}}{x!}


                                                           for x ∈ N ∪ {0}

                       =  0 otherwise --------------------------------------(1)

here, \lambda = 0.3 collision / month

No collision over a 4 month period means no collision per month or X =0

Putting X = 0 in (1) we get,

         P(X = 0) = \frac{e^{-0.3}\times {\0.3}^{0}}{0!}


                      \simeq 0.7408182207 ------------------------------------(2)

Now, since we are calculating  this for 4 months,

so, P(No collision in 4 month period)

     =0.7408182207^{4}

     \simeq 0.3012  -----------------------------------------------------------(3)

2 collision in 2 month period means 1 collision per month or X =1

Putting X =1 in (1) we get,

           P(X =1) = \frac{e^{-0.3}\times {\0.3}^{1}}{1!}


                      \simeq 0.2222454662 ------------------------------------(4)

Now, since we are calculating this for 2 months, so ,

P(2 collisions in 2 month period)

                =0.2222454662^{2}

                \simeq 0.0494 -----------------------------------------(5)

1 collision in 6 months period means

                                \frac{1}{6} collision per month

Now, P(1 collision in 6 months period)

= P( X = 1/6]  (which is to be estimated)

=\frac {P(X=0)\times 5 + P(X =1)\times 1}{6}

= \frac {0.7408182207 \times 5 + 0.2222454662 \times 1}{6}[/tex]

\simeq 0.6543894283-------------------------------------------(6)

So,

P(1  collision in 6 month period)

  =  0.6543894283^{6}

   \simeq 0.0785267444 ------------------------------------------------(7)

So,

P(No collision in 6 months period)

  = (P(X =0)^{6}

   \simeq 0.1652988882 ---------------------------------(8)

so,

P(1 or fewer collision in 6 months period)

= (8) + (7 ) = 0.0785267444 +0.1652988882

\simeq  0.2438 ---------------------------------------------(9)          

7 0
3 years ago
Find the measures of ∠B and ∠C. PLEASE HELP!!
BartSMP [9]

It's an isosceles triangle, therefore m∠B = m∠C.

We have the equation:

2x + 10 = 3x - 5      <em>subtract 10 from both sides</em>

2x = 3x - 15     <em>subtract 3x from both sides</em>

-x = -15     <em>change the signs</em>

x = 15

m∠B = (2x + 10)°

m∠B = (2 · 15 + 10)° = (30 + 10)° = 40°

We know, the sum of measures of a tringle is equal 180°.

m∠A + m∠B + m∠C = 180°

m∠B = m∠C = 40°

<h3>Answer: ∠B = 40° and ∠C = 40°</h3>
8 0
3 years ago
Help me please i’m dying and i’m just dying help
photoshop1234 [79]

Answer:

70

Step-by-step explanation:

verticle angles are congruent (the same) so if 1 is 110 than 4 is 110. also same side interior angles are supplementary (equal to 180) meaning 6 is 70. If verticle angles are congreunt then 7 also equals 70

3 0
3 years ago
Point C is the center of dilation. Line segment B A is dilated to create line segment B prime A prime. The length of C A is 4. T
saw5 [17]

Answer:

Step-by-step explanation:

Given

See attachment for figure

CA = 4

CA' = 16

Required

The scale factor (k)

Since point C is the center of dilation, the scale factor (k) is calculated using:

k = \frac{CA + CA'}{CA}

So, we have:

k = \frac{4+16}{4}

k = \frac{20}{4}

k = 5

8 0
2 years ago
ASAP HELP TYYY
deff fn [24]
It is $4.68. You do $58.45 times 0.08, which is $4.676, but you round that to $4.68.
5 0
2 years ago
Read 2 more answers
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