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salantis [7]
3 years ago
5

5-2×=13 cual es el numero para 2x​

Mathematics
1 answer:
olya-2409 [2.1K]3 years ago
3 0

Answer: 39

Step-by-step explanation: x=13. so 5-2=3 x 13 = 39   espero que esto ayude :)

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Is this the correct answer?
charle [14.2K]
Yes, it is right... you correctly distributed the negative, and combined like terms... great job!
6 0
3 years ago
Solve using substitution x = 3y + 1 2x + 4y = 12​
Free_Kalibri [48]

Answer:

x = 4

y = 1

Step-by-step explanation:

x = 3y + 1 (Multiply everything by -2)

2x + 4y = 12​ (Transfer 4y to the right of the = sign)

2x = -4y + 12

-2x = -6y - 2

0 = -10y + 10

-10 = -10y

y = 1

x = 3y + 1

x = 3(1) + 1

x = 3 + 1

x = 4

4 0
3 years ago
Please Help I Don't Understand.
lyudmila [28]

BE and CD are parallel, so the triangles ABE and ACD are similar. Then the following relation holds:

AE/AD = AB/AC

10/(10 + 8) = x/(x + 6)

Solve for x :

10 (x + 6) = x (10 + 8)

10x + 60 = 18x

8x = 60

x = 60/8 = 7/5

6 0
2 years ago
Examine the graph of the logarithmic function f(x).
Eduardwww [97]

Answer:

The function f(x) has a vertical asymptote at x = 3

Step-by-step explanation:

We can define an asymptote as an infinite aproximation to given value, such that the value is never actually reached.

For example, in the case of the natural logarithm, it is not defined for x = 0.

Then Ln(x) has an asymptote at x = 0 that tends to negative infinity, (but never reaches it, as again, Ln(x) is not defined for x = 0)

So a vertical asymptote will be a vertical tendency at a given x-value.

In the graph is quite easy to see it, it occurs at x = 3 (the graph goes down infinitely, never actually reaching the value x = 3)

Then:

The function f(x) has a vertical asymptote at x = 3

6 0
3 years ago
I need help number 13 and 14, how can I find x?
Alex73 [517]
#13.
x = 50

#14
x = 142
7 0
3 years ago
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