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3 years ago

WILL GIVE BRAINLIEST

Mathematics

2 answers:

ad-work [718]3 years ago

4 0

The correct answer would be 1in, if you want to check and see if im right use a 12 inch ruler and check

hope this helps out.

9966 [12]3 years ago

3 0

I am guessing 1/4 inch

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If 2x=8, then x=4<br><br> Name the property being illustrated in this expression

Kobotan [32]

2x4=8 is the expression gets the answer

4 0

3 years ago

Need a little help with one please

Pani-rosa [81]

Answer:

That would be the side-side-side (SSS) postulate, which states that if all the sides of a triangle are in a fixed ratio to all the corresponding sides of another triangle, then the two triangles are said to be congruent.

Step-by-step explanation:

Looking at triangles ABC and DEF, we notice that:

$\frac{AB}{DE} = \frac{AC}{DF}=\frac{BC}{EF}$

since

$\frac{3}{18} = \frac{6}{36}=\frac{7}{42}=\frac{1}{6}$

Let me know if you have further questions.

4 0

3 years ago

X-y=1 this is on my homerork assignment and i want to know how to grap it

Alecsey [184]

To more easily graph this, convert it to slope-intercept form (y = mx + b, where m is the slope and b is the y-intercept):

x - y = 1
-y = -x + 1
y = x - 1

The slope is 1 and the y-intercept is -1. To graph this, plot the point (0, -1) and count 1 unit down and 1 unit to the right. Do this once more, connect the points, and you have your line.

Hope this helps.

8 0

3 years ago

Write the number in two other forms

notka56 [123]

..wheres the number....?

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3 years ago

What are the coordinates of the endpoints of the midsegment for DEF that is parallel to DE

Nutka1998 [239]

Answer:

$\left(\dfrac{x_D+x_F}{2},\dfrac{y_D+y_F}{2}\right),$ $\left(\dfrac{x_E+x_F}{2},\dfrac{y_E+y_F}{2}\right).$

Step-by-step explanation:

Let points D, E and F have coordinates $(x_D,y_D),\ (x_E,y_E)$ and $(x_F,y_F).$

1. Midpoint M of segment DF has coordinates

$\left(\dfrac{x_D+x_F}{2},\dfrac{y_D+y_F}{2}\right).$

2. Midpoint N of segment EF has coordinates

$\left(\dfrac{x_E+x_F}{2},\dfrac{y_E+y_F}{2}\right).$

3. By the triangle midline theorem, midline MN is parallel to the side DE of the triangle DEF, then points M and N are endpoints of the midsegment for DEF that is parallel to DE.

6 0

3 years ago