Hello :
<span> sin 2x = sin x and 0 ≤ x ≤ 2π.
all solutions :
2x= x +2k</span>π or x= π -x +2kπ ..... k in : Z
x = 2kπ or : x = π/2 + kπ
but :
<span>0 ≤ x ≤ 2π
</span><span>all values of x such that sin 2x = sin x and 0 ≤ x ≤ 2π are :
</span>k = 0 : x=0 , x= π/2
k=1 : x=2 π , x=3π/2
Answer:
Terms (Variables) = x , d . Their corresponding coefficients = n^2 , 1/2 . Constant = 6
Step-by-step explanation:
6 + n x n + 1/2d
6 + n^2 x + 1/2d
Terms (Variables) = x , d . Their corresponding coefficients = n^2 , 1/2 . Constant = 6
Answer:
I have made it in above pic
Answer:
B, it's the only plausible one. A is wrong because the value would be above 180°
