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anyanavicka [17]
3 years ago
14

3. Explain why one side of the single magnet attracted the metal surface, but repelled the stack of magnets

Physics
2 answers:
valina [46]3 years ago
7 0

Answer:

Explained

Explanation:

one side of the single magnet attracted the metal surface, but repelled the stack of magnets because  magnet's both poles  try to attract by inducing opposite pole on the metal surface,but the pole closer to the metal is able to induce more magnetic character .so, attractive force due to this is more strong as the distance is also less as compared to the other pole.

Sati [7]3 years ago
5 0

Explanation:

Magnets have the property where opposite poles attract each other and same poles repel each other. The single magnet in this case repels the stack of magnets which means that the poles of the single magnet and stack of magnet are same.

Metals are not permanent magnets. Temporary magnetism can be induced in metal by bringing a magnet close to it. The poles of the metal surface will be such that it is attracted by the magnet.

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A horizontal force of 100 N is required to push a 50 kg crate across a factory floor at a constant speed. What is the accelerati
luda_lava [24]

Answer:

a = 2m/s^2

Explanation:

Force (F) = 100 N

Mass (m) = 50 kg

Here,

F = m×a

100 = 50 × a

a = 100÷50

a = 2m/s^2

Thus, the acceleration on the cart is a = 2m/s^2

-TheUnknownScientist

6 0
2 years ago
What is the speed of a wave with a wavelength of 3 m and a frequency of .1Hz?
Yuri [45]
We know,
Speed = Frequency * Wavelength 
Speed = 3 * 0.1 m/s   [hertz = 1/sec.]
So, your final answer is 0.3 m/s

Hope this helps!!
6 0
3 years ago
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Glucose can have a straight chain of ______________ atoms or, more commonly, form a _____________ structure.
vovikov84 [41]
Lipids and <span>Polysaccharides r the answers hoped i helped</span>
6 0
2 years ago
A jogger runs 20 mi West and then 6.0 mi North. Find the magnitude and direction of the resultant displacement.
Black_prince [1.1K]

Answer:

The magnitude of the resultant displacement is 21 mi and its direction is 16.7° north of west

Explanation:

Hi there!

Please see the figure for a better understanding of the problem. The total displacement vector will be the sum of both displacements:

The vector for the first displacement is:

First displacement = (20 mi, 0)

The second displacement:

Second displacement = (0, 6.0 mi)

The resultant displacement will be:

R = (20 mi, 0) + (0, 6.0 mi) = (20 mi + 0, 0 + 6.0 mi) = (20 mi, 6.0 mi)

The magnitude of this vector will be:

|R| = \sqrt{(20 mi)^{2} + (6.0 mi)^{2}} = 21 mi

The magnitude of the vector displacement is 21 mi.

To find the direction of the vector R, we have to apply trigonometry:

In a right triangle the following trigonometric rule applies:

cos θ = adjacent side to the angle/ hypotenuse

In this case:

cos θ = 20 mi / magnitude of R

θ = 16.7°

The direction of the vector is 16.7° north of west.

4 0
3 years ago
A 0.2-stone is attached to a string and swung in a circle of radius 0.6 m on a horizontal and frictionless surface. If the stone
Nikitich [7]

Answer:

2960 N

Explanation:

Convert rev/min to rad/s:

150 rev/min × (2π rad/rev) × (1 min / 60 s) = 50π rad/s

Sum of forces in the centripetal direction:

∑F = ma

T = m v² / r

T = m ω² r

T = (0.2 kg) (50π rad/s)² (0.6 m)

T = 2960 N

3 0
3 years ago
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