A horizontal force of 750 N is needed to overcome the force of static friction between a level floor and a 250-kg crate. If g-9.
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Answer:
Knowing we only have one load applied in just one direction we have to use the Hooke's law for one dimension
ex = бx/E
бx = Fx/A = Fx/π
Using both equation and solving for the modulus of elasticity E
E = бx/ex = Fx / πex
E =
Apply the Hooke's law for either y or z direction (circle will change in every direction) we can find the change in radius
ey = (бy - v (бx + бz)) =
бx
= =
Finally
ey = Δr / r
Δr = ey * r = 10 *
Δd = 2Δr =
Explanation: