Answer:
There are 5.69*10²⁴ molecules in 9.45 moles.
Explanation:
The mole is defined as the amount of matter that particles have, that is, atoms and elementary entities.
Avogadro's Number or Avogadro's Constant is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023*10²³ particles per mole and represents a quantity without an associated physical dimension. Avogadro's number applies to any substance.
Then the following rule of three can be applied: if 1 mole contains 6.023 * 10²³ molecules, 9.45 moles, how many molecules will it have?

Solving:
amount of molecules= 5.69*10²⁴⁴ molecules
<u><em>There are 5.69*10²⁴ molecules in 9.45 moles.</em></u>
Reaction of Copper with Mercuric Nitrate is as follow,
Cu + Hg(NO₃)₂ → Cu(NO₃)₂ + Hg
According to equation,
1 Mole of Cu reacts to form = 1 Mole of Hg
So,
1.20 Moles of Cu will react to produce = X Moles of Hg
Solving for X,
X = (1.20 mol × 1 mol) ÷ 1 mol
X = 1.20 mol of Hg
Result:
1.20 mole of Cu when reacted with mercuric nitrate produces 1.20 moles of Hg.
The correct answer to the question above is
:
(c.) agriculture.
Agriculture is the greatest use of groundwater. Groundwater is a water found in the underground or beneath the Earth's surface, in the cracks and soil spaces.
Explanation:
Food and agriculture are the largest purchasers of water, requiring one hundred times more than we use for individual needs. Up to 70 % of the water we take from rivers and groundwater goes into irrigation, about 10% is used in residential applications and 20% in industry. Groundwater is the water today underneath Earth's outside in soil pore spaces and in the fractures of rock structures. A unit of rock or an unconsolidated alluvium is described as an aquifer when it can generate a usable quantity of water.
Answer:
2NaOH + CO2 -> Na2CO3 + H2O
1) Find the moles of each substance

2) Determine the limitting reagent

∴ Carbon dioxide is limitting as it has a smaller value.
3) multiply the limiting reagent by the mole ratio of unknown over known
n(H2O ) = 0.3976369007 × 1/2
= 0.1988184504 moles
4) Multiply the number of moles by the molar mass of the substance.
m = 0.1988184504 × (1.008 × 2 + 16.00)
= 0.1988184504 × 18.016
= 3.581913202 g
Explanation: