11.

Consider the following reaction:2NOBr(g) 2NO(g) + Br2(g)If 0.412 moles of NOBr(g), 0.678 moles of NO, and 0.224 moles of Br2 are

Vaselesa [24]

Answer: $K_c=0.0587M$

Explanation: The given chemical reaction is:

$2NOBr(g)\rightleftharpoons 2NO(g)+Br_2(g)$

Equilibrium constant (Kc) in general is written as:

$K_c=\frac{[products]}{[reactants]}$

Note:- Coefficients are written as their powers

So, the Kc expression for the above reaction will be:

$K_c=\frac{[NO]^2[Br_2]}{[NOBr]^2}$

Equilibrium moles are given for all of them. Let's divide the moles by given liters to get the concentrations.

$[NOBr]=\frac{0.412mol}{10.3L}$ = 0.040 M

$[NO]=\frac{0.678mol}{10.3L}$ = 0.0658 M

$[Br_2]=\frac{0.224mol}{10.3L}$ = 0.0217 M

Plug in the values in the equilibrium expression to calculate Kc.

$K_c=\frac{(0.0658M)^2(0.0217M)}{(0.040M)^2}$

$K_c=0.0587M$

4 0

3 years ago

6. How many sections are there to an SDS for a given chemical? *

Ad libitum [116K]

The answer would be 16

4 0

3 years ago

Both suspensions and colloids are heterogeneous mixtures. Define and characterize a colloid, listing similarities and difference

Anna11 [10]

<span>a homogeneous, noncrystalline substance consisting of large molecules or ultramicroscopic particles of one substance dispersed through a second substance. Colloids include gels, sols, and emulsions; the particles do not settle and cannot be separated out by ordinary filtering or centrifuging like those in a suspension</span>

3 0

3 years ago

Read 2 more answers

Zinc metal reacts with hydrochloric acid to produce zinc(II) chloride and hydrogen gas. How many liters of hydrogen gas will be

AleksAgata [21]

Answer:

0.120 L of hydrogen gas will be produced

Explanation:

Step 1: Data given

Mass of zinc = 10.0 grams

Volume of hydrochloric acid = 23.8 mL

Molarity of hydrochloric acid = 0.45 M

Molar mass of zinc =65.38 g/mol

Step 2: The balanced equation

Zn + 2HCl → ZnCl2 + H2

Step 3: Calculate moles Zinc

Moles Zn = mass Zn / molar mass Zn

Moles Zn = 10.0 grams / 65.38 g/mol

Moles Zn = 0.153 moles

Step 4: Calculate moles HCl

Moles HCl = molarity * volume

Moles HCl = 0.45 M * 0.0238 L

Moles HCl = 0.01071 moles

Step 5: Calculate limiting reactant

For 1 mol Zn, we need 2 moles HCl to produce 1 mol ZnCl2 and 1 mol H2

HCl is the limiting reactant. It will completely be consumed (0.01071 moles)

Zn is in excess. There will react 0.01071/2 = 0.005355 moles

There will remain 0.153 - 0.005355 = 0.147645 moles

Step 6: Calculate moles H2

For 1 mol Zn, we need 2 moles HCl to produce 1 mol ZnCl2 and 1 mol H2

For 0.01071 moles HCl we'll have 0.005355 moles H2

Step 7: Calculate volume H2

1 mol at STP = 22.4 L

0.005355 moles = 22.4 * 0.005355 = 0.120 L = 120 mL

0.120 L of hydrogen gas will be produced

4 0

4 years ago

Show that the speed of an electron in the nth bohr orbit of hydrogen is Î±c/n, where Î± is the fine structure constant. what wou

PtichkaEL [24]

<span>In the Bohr model we assume that angular momentum is quantised: L = mvr = nâ„Ź From this you can find the expression for the tangential velocity of the electron. You then need to find the expression for the Bohr radius for a particular value of n, which turns out to be (for Z = 1, for Hydrogen-like atoms just replace e^2 with Z(e^2)): rn=4Ď€Ďµ0â„Ź2n2/me2 When you sub in for r you get: vn=e2/4Ď€Ďµ0â„Ź From this you should be able to work out what the fine structure constant is - just compare the equation you were given to the one above. In undergrad physics courses the name "fine structure constant" is often applied to a few dimensionless constants that all look similar. It's just a number that happens to arise in a lot of Quantum Mechanical situations.</span>

4 0

3 years ago