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sergiy2304 [10]
2 years ago
15

Most scientific investigations are driven by the desire to answer a question. true or false

Chemistry
1 answer:
beks73 [17]2 years ago
8 0
This awnser will be true because that's what it is and will always be
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A sample of gas in a balloon has an initial temperature of 37C and a volume of 1560 L. If the temperature changes to 82C , and t
FromTheMoon [43]

Answer:

First part: The new volume of the gas is 1786 Liters.

Second part: The temperature required to change the volume of the gas sample is 347 °C

Explanation:

We assume the Charles - Gay Lussac law where, in constant pressure, volume of a gas changes directly proportional to Temperature (in Kelvin)

V1 / T1  = V2/T2

37°C + 273 = 310 K

82°C + 273 = 355 K

1560L / 310°K = V2 / 355K

(1560 / 310) . 355 = V2

1786 L = V2

1560 L / 310 K = 3120 L / T2

T2 = 3120 L . (310 K / 1560 L)

T2 = 620 K

620K - 273 = 347°C

6 0
2 years ago
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harina [27]
Honestly me too tbhhhhhhhhh
6 0
2 years ago
What is the number of moles in 3.0 X 10^24 atoms of Carbon
evablogger [386]

Answer:the number of moles represented by 3.0 x 10^24 atoms of Ag is 0.500mol 0.500 m o l .

Explanation:

4 0
11 months ago
A buffer contains 0.18 mol of propionic acid (C2H5COOH) and 0.26 mol of sodium propionate (C2H5COONa) in 1.20 L. What is the pH
Yuki888 [10]

Answer:

1) pH = 5.05

2) pH = 5.13

3) pH = 4.97

Explanation:

Step 1: Data given

Number of moles of propionic acid = 0.18 moles

Number of moles sodium propionate = 0.26 moles

Volume = 1.20 L

Ka = 1.3 * 10^-5    → pKa = 4.989

Step 2: Calculate concentrations

Concentration = moles / volume

[acid]= 0.18/ 1.2 =0.150 M

[salt]= 0.26/ 1.3 = 0.217 M

pH = 4.89 + log(0.217/0.150)=<u>5.05</u>

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What is the pH of the buffer after the addition of 0.02 mol of NaOH?

moles acid = 0.18 - 0.02 = 0.16

[acid]= 0.16/ 1.2=0.133 M

moles salt = 0.26 + 0.02 = 0.28

[salt]= 0.28/ 12=0.233

pH = 4.89 + log 0.233/ 0.133 = 5.13

What is the pH of the buffer after the addition of 0.02 mol of HI?

moles acid = 0.18+ 0.02 = 0.20 moles

[acid]= 0.20/ 1.2 = 0.167 M

[salt]= 0.26 - 0.02= 0.24 moles

[salt]= 0.24/ 1.2 = 0.20 M

pH = 4.89 + log 0.20/ 0.167= 4.97

8 0
2 years ago
If water is added to a 0.70 molar solution of CuSO4 what will change
lana [24]

Answer:

B. Molarity will decrease

Explanation:

Molarity is one of the measures of the molar concentration of a solution. It is calculated by dividing the number of moles of the solute by the volume of the solvent. This means that the higher the amount of solute in relation to the volume of solvent, the higher the molarity of that solution.

In essence, adding water to a solution dilutes it i.e it increases the solvent's volume in relation to the solute, causing the molarity to decrease. In a nutshell, diluting a solution (by adding water or more solvent) causes the molarity of such solution to decrease. For example, if water is added to a 0.70 molar solution of CuSO4, the molarity of the solution will DECREASE.

7 0
2 years ago
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