Answer:
RTBWETERTBWETBWETWTBTBAnswer:
Explanation:
Answer:
Explanation:
Answer:
BSRBTSTR
Explanation:
Answer:ETRTSBT
REBREGERB
Explanation:
Answer:
REBRBETSERTETREERSTSER
Explanation:SETRSBE
Answer:RETERTSE
TBESRBTBTRE
Explanation:
Explanation:
Answer:1.
1.Balanced equation
C4H10 + 9 02 ==> 5H20 +4CO2
2. Volume of CO2 =596L
Explanation:
1.Combustion of alkane is the reaction of alkanes with Oxygen. And the general equation for the combustion is;
CxHy +( x+y/4) O2 ==> y/2 02 + xCO2
Where x and y are number of carbon and hydrogen atoms respectively.
For butane (C4H10)
x=4 and y=10
Therefore
C4H10 + 9 02 ==> 5H20 +4CO2
2. Mass of butane = 0.360kg
Molar mass of C4H10 = ( 12×4 + 1×10)
= 48 +10=58g/mol= 0.058kg/mol
Mole = mass/molar mass
Mole = 0.360/0.058= 6.2moles
From the stoichiometric equation
1mole of C4H10 will gives 4moles of CO2
Therefore
6.2moles of C4H10 will gives 4 moles of 24.8 moles of CO2
Using the ideal gas equation
PV=nRT
P= 1.0atm
V=?
n= 24.8mol.
R=0.08206atmL/molK
T=20+273=293
V= 24.8 × 0.08206 × 293
V= 596L
Therefore the volume of CO2 produced is 596L
The oxygen family, also called the chalcogens, consists of the elements found in Group 16 of the periodic table and is considered among the main group elements. It consists of the elements oxygen, sulfur, selenium, tellurium and polonium.
/the next low tide will be on monday 5th june at 2:30
Answer:
Kc = [C2H5OH]/{[C2H4][H2O]}
[H2O] = [C2H5OH]/{[C2H4] x Kc}
[H2O] = 1.69/(0.015 x 9.0 x 10^3) = 0.013 M
Explanation:
Kc is the equilibrium constant, it is egal to the product of the equilibrium concentration of the product dived by the product of the equilibrium concentration of the reactants.
with that formula and what is given, male the equilibrium concentration of H2O the subject of the formula and calculate its concentration by substituting given values.
