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lesya [120]
3 years ago
15

Find g prime left parenthesis x right parenthesis for the given function. Then find g prime left parenthesis negative 3 right pa

renthesis​, g prime left parenthesis 0 right parenthesis​, and g prime left parenthesis 2 right parenthesis. g left parenthesis x right parenthesis equals StartRoot 4 x EndRoot
Mathematics
1 answer:
Romashka-Z-Leto [24]3 years ago
4 0

Answer: For x = 0, -3, our expression is undefined and for x = 2, we have 0.707.

Step-by-step explanation: From the question, we have

g(x) = \sqrt{4x}

Simplifying the right-hand side, we have:

g(x) = 2x^{1/2}

Differentiating with respect to $x$ using the second principle, we have,

g'(x) =  2 * \frac{1}{2} * x^{\frac{1}{2} - 1}

= x^{-1/2}

So from the indical laws,   g'(x) =x^\frac{-1}{2} = 1/\sqrt{x}  

For values of g'(x) when x = -3, we have

g(x) = 1/\sqrt{-3}

g(x) is undefined for values of x when x is -3 since the square root of a negative number is not defined. However, using complex solution we have

g(x) = 1/\sqrt{-3}

But \sqrt{-1} = i; then \sqrt{-3} = \sqrt(-1 * 3)

This is same as \sqrt(-1) * \sqrt(3)

And then we have 1.732i

For x = 2, we have

g’(2) = 1/\sqrt (x)

= 1/\sqrt(2) = 0.707

For x = 0, we have

g’(0) = 1/\sqrt (0)

 = 1/0

Here again for x = 0, our expression is undefined.

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Answer:

They encircle the planet 3.76\times 10^{11} times.

Step-by-step explanation:

Consider the provided information.

We have 2.5 mole of dust particles and the Avogadro's number is 6.022\times 10^{23}

Thus, the number of dust particles is:

2.5\times 6.022\times 10^{23}=15.055\times 10^{23}

Diameter of a dust particles is 10μm and the circumference of earth is 40,076 km.

Convert the measurement in meters.

Diameter: 10\mu m\times \frac{10^{-6}m}{\mu m} =10^{-5}m

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Circumference in meters:

40,076km\times \frac{1000m}{1km}=40,076,000 m

Therefore,

\frac{1.5055\times 10^{19}}{40,076,000} = 3.76\times 10^{11}

Hence, they encircle the planet 3.76\times 10^{11} times.

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