Question

Write a net ionic equation for the overall reaction that occurs when aqueous solutions of sodium hydroxide and oxalic acid (H2C2O4) are combined. Assume excess base. Use the pull-down boxes to specify states such as (aq) or (s).

Answer 1

Answer:

The  net ionic equation for the overall reaction is

          $H_2C_2O_4{(aq)} + 2OH^-_{(aq)} ----> C_2O_4^{2-}_{(aq)} + 2H_2O_{(l)}$

Explanation:

The molecular formula for sodium hydroxide is  $NaOH$ while the molecular formula for oxalic acid is given as ($H_2 C_2 O_4$)

   Now the balanced chemical equation for this reaction is

           $H_2C_2 O_4_{(aq)} + 2NaOH_{(aq)} ----> Na_2C_2O_4_{(aq)} + 2H_2O_{(l)}$

The procedure for the ionic equation is

    $H_2 C_2O_4 _{(aq)} + 2 Na^+ _{(aq)} + 2OH^-_{(aq)} ---->2Na^+ _{(aq)} + C_2O_4^{2- }_{(aq)} + 2H_2O_{(l)}$

Here $Na^+$ is the sodium ion

       $OH^-$ is the hydroxide ion

       $C_2O_4^{2-}$ is the oxalate ion

Note: The dissociation of oxalic equation is not complete because it is a weak acid

Looking at this equation we see that $Na^+$ is common on both sides of the equation so we cancel it out so the equation becomes

           $H_2C_2O_4{(aq)} + 2OH^-_{(aq)} ----> C_2O_4^{2-}_{(aq)} + 2H_2O_{(l)}$

       

Answer 2

Answer:

Oxalic acid is a dicarboxylic acid and forms sodium salt with NaOH and water

Explanation: