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Explanation:
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Aluminum Iodate
Answer:1/4 ml
Density=8g/ml
Mass=2g
Volume=mass/density
Volume=2/8
Volume=1/4 ml
0.0521 M
HClO2 + NaOH ---> NaClO2 + H2O
M(HClO2)V(HClO2) = M(NaOH)V(NaOH)
M(HClO2)*41.6 mL = 0.146 M*14.85 mL
M(HClO2) = 0.146*14.85/41.6 M = 0.0521 M
1. State problem
2. Form hypothesis
3. Conduct experiment
4. Interpret data
5. Draw conclusion
