The solution would be like
this for this specific problem:
<span>(78.6 kJ) / (92.0 g /
(46.0684 g C2H5OH/mol)) = 39.4 kJ/mol </span>
<span>39.3 </span>
So the approximate molar
heat of vaporization of ethanol in kJ/mol is 39.3.
I hope this answers your question.
Answer:
4477381.7 calories/pound
Explanation:
It is given that,
When a candle burns it produced 41,300 Joules per 1 gram.
We need to convert it into calories per pound.
We know that,
1 cal = 4.184 J
⇒ 1 J = (1/4.184) cal
1 pound = 453.592 grams
⇒1 g = (1/453.592) pounds
Now,
Hence, 41,300 Joules/gram = 4477381.7 calories/pound.
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Heat Transfer Lab
The following represents a lab set up for heat transfer. The cup on the left started with boiling water at 100 degrees C and the cup on the right has water at 20 degrees C. There is an aluminum bar between the two cups allowing heat to transfer from one cup into the other. The set up will be left alone for 20 minutes and temperatures of each cup of water will be recorded every minute for 20 minutes.
mag-aral ka
