How many moles of copper atoms are in 150g of copper metal

1 answer:

3 0

The answer to this question would be: 2.36 mol

To answer this question, you need to know the molecular weight of copper. Molecular weight determines how much the weight of 1 mol of a molecule has. Copper molecular weight about 63.5g/mol. Then, the amount of mol in 150g copper should be: 150g / (63.5g/mol)= 2.36 mol

You might be interested in

some constellations, such ad Ursa Minor, are visible in the sky year-round; other contellations appear for only part of the year

worty [1.4K]

While most constellations are only visible to us in different seasons, some are always there 24/7/365 because they are positioned close to the Polar Axis, or the Polaris.

5 0

3 years ago

Because of the high number of hydrogen bonds, water exhibits ____________ , meaning the molecules cling together. under ordinary

Katena32 [7]

Answer: 1) "cohension" ;

2) "liquid" .
____________________________________________________________

4 0

4 years ago

Which physical method can separate a mixture of steel ball bearings and marbles

Lana71 [14]

Sorting is a method that could separate those materials

6 0

3 years ago

Read 2 more answers

Hich of these correctly defines the pOH of a solution?

kramer

The log of the hydronium ion concentration

8 0

3 years ago

Read 2 more answers

choose any bases that will selectively deprotonate the above acid, that is, any bases that will favor the formation of products.

Zanzabum

In order to deprotonate an acid, we must remove protons in order to achieve a more stable conjugate base. For this example, we can use the relationship between carboxylic acid and hydroxide.

Deprotonation is the removal of a proton from a specific type of acid in reaction to its coming into contact with a strong base. The compound formed from this reaction is known as the conjugate base of that acid. The opposite process is also possible and is when a proton is added to a special kind of base. This is a process referred to as protonation, which forms the conjugate acid of that base.

For the example we have chosen to give, the conjugate base is the carboxylate salt. This would be the compound formed by the deprotonated carboxylic acid. The base in question was strong enough to deprotonate the acid due to the greater stability offered as a conjugated base.

To learn more visit:

brainly.com/question/5613072?referrer=searchResults

8 0

3 years ago