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2 years ago

How many moles of copper atoms are in 150g of copper metal

1 answer:

3 0

The answer to this question would be: 2.36 mol

To answer this question, you need to know the molecular weight of copper. Molecular weight determines how much the weight of 1 mol of a molecule has. Copper molecular weight about 63.5g/mol. Then, the amount of mol in 150g copper should be: 150g / (63.5g/mol)= 2.36 mol

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State two differences between physical change and chemical change

Lubov Fominskaja [6]

Answer:

See explanation

Explanation:

1) Physical change is usually reversible, while chemical change isn't

2) Chemical change involves the change of chemical composition of matter while physical change doesn't

6 0

2 years ago

Read 2 more answers

3. How much power is required to pull a sled if you use<br>60j of work in secound?<br>

JulijaS [17]

Answer:

The answer is 60W

Power = Work done/ time

time = 1 second

Work done = 60J

Power = 60/1

= 60W

Hope this helps.

3 0

3 years ago

Concrete is made of an uneven mixture of gravel, sand, and water. It is _____. homogenous heterogeneous a solution a solute

Kobotan [32]

heterogeneous, because it does not have a uniform texture

hope That helps

7 0

2 years ago

A student plans to use a density versus solution concentration standard curve to identify the sodium chloride concentration in a

Art [367]

Answer:

a. 0.50 g, 1.0 g, 1.5 g, 2.0 g, 2.5 g;

g. 0.1 g, 0.5 g, 1.0 g, 1.5 g, 2.0 g

Explanation:

The percent mass is defined as a ratio between the mass of a solute and mass of a solution:

$\omega = \frac{m_{solute}}{m_{solution}}\cdot 100\%$

Since solution only consists of a solute and solvent, express its mass as:

$m_{solution} = m_{solute} + m_{solvent}$

Then:

$\omega = \frac{m_{solute}}{m_{solution}}\cdot 100\%=\frac{m_{solute}}{m_{solute} + m_{solvent}}$

Firstly, solve for how much mass is required to prepare 3.0 %. Let's say, we have x g of the solute:

$0.03 = \frac{x}{30.0 + x}\therefore x = 0.03(30.0 + x)$

$x = 0.90 + 0.03x$

$0.97x = 0.90\therefore x = 0.93 g$

Similarly, solve for 6.0 %, let's say, we have x g of the solute again:

$0.06 = \frac{x}{30.0 + x}\therefore x = 0.06(30.0 + x)$

$x = 1.80 + 0.06x$

$0.94x = 1.80\therefore x = 1.91 g$

Hence, masses should be in a range of 0.93 g to 1.91 g.

7 0

3 years ago

How are half life and radioactive decay related

hoa [83]

Answer : Half life and radioactive decay are inversely proportional to each other.

Explanation :

The mathematic relationship between the half-life and radioactive decay :

$N=N_oe^{-\lambda t}$ ................(1)

where,

N = number of radioactive atoms at time, t

$N_o$ = number of radioactive atoms at the beginning when time is zero

e = Euler's constant = 2.17828

t = time

$\lambda$ = decay rate

when $t=t_{1/2}$ then the number of radioactive decay become half of the initial decay atom i.e $N=\frac{N_o}{2}$ .

Now substituting these conditions in above equation (1), we get

$\frac{N_o}{2}=N_oe^{-\lambda t_{1/2}}$

By rearranging the terms, we get

$\frac{1}{2}=e^{-\lambda t_{1/2}}$

Now taking natural log on both side,

$ln(\frac{1}{2})=-\lambda \times t_{1/2}$

By rearranging the terms, we get

$t_{1/2}=\frac{0.693}{\lambda}$

This is the relationship between the half-life and radioactive decay.

Hence, from this we conclude that the Half life and radioactive decay are inversely proportional to each other. That means faster the decay, shorter the half-life.

3 0

3 years ago