Answer:
The correct answer is the option A: True.
Explanation:
To begin with, the contracts inside the law are regulated by the Anglo-America common law that defines a contract as the agreement between two or more parties in which they establish the basis and principles of the agreement and the clauses that could cause to end the contract. Moreover, a contract is also part of the civil law and therefore that it does not implicate the public as a whole in any way due to the fact that in order to be a correct contract the parties must accept the bond between only them and nobody else.
Answer:
The amount I can afford to spend each year is $133,241.15
Explanation:
The amount I can afford to spend each year can be determined using the formula for present value of annuity due which is given below:
PV(Annuity due)=A*(1-(1+r)^-N)/r
PV is the present value of the investment which is $1.5 million
A is the annual spending which is unknown
r is the rate of return on the investment at 8% per year
N is the duration of investment which is 30 years
The formula can be rewritten as
A=PV/(1-(1+r)^-N)/r
(1-(1+r)^-N)/r=1-(1+8%)^-30/8%
=1-(1+0.08)^-30/0.08
=(1-0.099377333
)/0.08
=11.25778334
11.25778334 is known as annuity factor
A=$1500000/11.25778334
A=$133,241.15
Answer:
Present Value of first option:
= -105,000 + 35,000/ (1 + 9%) + 35,000/(1 + 9%)² + 35,000/(1 + 9%)³ + 35,000/(1 + 9%)⁴
= -105,000 + 113,390.19
= $8,390.20
Present Value of second option:
= -105,000 + 152,500/ (1 + 9%)⁴
= -105,000 + 108,034.84
= $3,034.84
Answer:Many companies state their brand promise directly in words, using a short phrase called what? A. A warranty B. A customer mindset C. A corporate image D. A tagline
✓ D.
Answer:
a) 7.627144987
b) 5.605222315
c) 20.04031392
d) 10.17644951
Explanation:
We need to solve for years starting from the future value of a lump sum formula:

We use logarithmics properties and solve:

a)
log(1655/800)/log1.1 = n
7.627144987
b)
log(4250/2491)/log1.08 = n
5.605222315
c)
log(392620/33905)/log1.13 = n
20.04031392
d)
log(214844/33600)/log1.20 = n
10.17644951