Answer:
If the amplitude of motion is doubled, so the mass swings 8 cm to one side and then the other, the period of the motion will be <u>2 s</u>.
Explanation:
As we know that time period of the motion of the simple pendulum is given as
here we know that
L = length of the pendulum
g = acceleration due to gravity
so as per above formula we know that time period of the pendulum is independent of the amplitude of the motion of the time period
So we will say that there is no change in the time period of the motion when we increase the amplitude of the motion of the given pendulum
The answer is D. water vapor water, ice. Have a good day :)
To solve this problem, it is necessary to apply the concepts related to the change of entropy in function of the Volume in two states due to the number of moles and the ideal gas constant, this can be expressed as
Where,
R = Gas constant
V = Volume (at each state)
At the same time the number of moles of gas would be determined by the ideal gas equation, that is,
Where,
P = Pressure
V = Volume
R = Gas Constant
T = Temperature
Using the value of moles to replace it in the first equation we have
Therefore the correct option is A.
Tycho Brahe ( 1546 - 1601 ) was a Danish astronomer known for his accurate astronomical and planetary observations. Tycho tried to produce a model with the best of both Ptolemy ( earth-centered solar system ) and Copernicus ( sun-centered solar system ).
Answer: B ) observation.
Answer:
a) 323.4J
b) 0J
c) -323.4J
Explanation:
a) W=Fd
F=ma
solve for acc. using kinematics
v^2=vo^2+2a(x)
8.41=2a(12)
4.205=a(12)
0.35=a
F=(77)(0.35)
F=26.95N
W=26.95*12...... W=323.4J
b) No acceleration, thus no force, thus no work!
c) W=Fd
F=ma
find acc. using kinematics: v^2=vo^2+2a(x)
0=(2.9^2)+2a(12)
0=8.41+2a(12)
-8.41=2a(12)
-4.205=a(12)
-0.35=a
F=(77)(-0.35)
F=-26.95N
W=(-26.95)(12)
W=-323.4J
Yes, work can be negative!