To find it, evaluate it at the endpoints and the vertex
in form
f(x)=ax²+bx+c
the x value of the vertex is -b/2a
given
c(t)=1t²-10t+76
x value of vertex is -(-10)/1=10
evaluate c(0) and c(13) and c(10)
c(0)=76
c(13)=115
c(10)=76
it reached minimum in 2000 and 2010
porbably teacher wants 2010
the min value is $76
Answer:
nearby -3
Step-by-step explanation:
When v^3 is -26, your v is equal to ![-\sqrt[3]{26}](https://tex.z-dn.net/?f=-%5Csqrt%5B3%5D%7B26%7D)
.
3^3 is 27, so v is nearby 3.
or, It would be nearby 3.9
Answer: x=15
Step-by-step explanation: Let's solve your equation step-by-step.
x+
1
/2
(x−5)=20
Step 1: Simplify both sides of the equation.
x+
1
/2
(x−5)=20
x+(
1
/2
)(x)+(
1
/2
)(−5)=20(Distribute)
x+
1
/2
x+ −5
/2
=20
(x+
1
/2
x)+(
−5
/2
)=20(Combine Like Terms)
3
/2
x + −5
/2
=20
3
/2
x + −5
/2
=20
Step 2: Add 5/2 to both sides.
3
/2
x + −5
/2 + 5
/2
=20+
5
/2
3
/2
x= 45
/2
Step 3: Multiply both sides by 2/3.
(
2
/3
)*(
3
/2
x)=(
2
/3
)*(
45
/2
)
x=15
Answer:
d = 6.997 or 7
Step-by-step explanation:
Use Pythagorean Theorem to find the diagonal of the end of the prism
2^2 + 3^2 = C^2 Simplify
4 + 9 = C^2 Add
13 = C^2 Take the square root of both sides
3.6 = C
Now plug this into the Pythagorean Theorem equation for the diagonal of the whole prism.
3.6^2 + 6^2 = d^2 Simplify
12.96 + 36 = d^2 Add
48.96 = d^2 Take the square root of both sides
6.997 = d This can be rounded up to 7, if needed
