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3 years ago

15

Enrique was one of the students surveyed. What is the probability that Enrique participates in after-school activities given tha

t he lives 7 miles from school?

1 answer:

mamaluj [8]3 years ago

3 0

Answer:

the probability would be low because of the long distance he would have travel

Step-by-step explanation:

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Number 2 I need help on how to solve it

Hunter-Best [27]

Let's simplify the following expression:

$\text{ }\frac{\text{ \lparen2x}^4\text{ - y}^6\text{z}^{-4})^2}{\text{ 2x}^2\text{z}^3}\text{ }\cdot\text{ }\frac{\text{ 6x}^5\text{y}^{-4}\text{z}^{-5}}{\text{ \lparen2x}^6\text{y}^3\text{z}^{-3})^2}$

We get,

$\text{ }\frac{(\text{2x}^4\text{ - y}^6\text{z}^{-4})^2}{\text{ 2x}^2\text{z}^3}\text{ }\cdot\text{ }\frac{6x^5y^{-4}z^{-5}}{(2x^6y^3z^{-3})^2}$ $\text{ }\frac{(2x^4-y^6z^{-4})^2(6x^5y^{-4}z^{-5})}{(2x^2z^3)(2x^6y^3z^{-3})^2}$ $\text{ }\frac{(4x^8\text{ - 4x}^4y^6z^{-4}\text{ + y}^{12}z^{-8})(6x^5y^{-4}z^{-5})}{(2x^2z^3)(4x^{12}y^6z^{-6})}$ $\text{ }\frac{24x^{13}y^{-4}z^{-5}\text{ - 24x}^9y^2z^{-9}\text{ + 6x}^5y^8z^{-13}}{8x^{14}y^6z^{-3}}$

4 0

1 year ago

I need this please help mee

zubka84 [21]

Answer:

A, 120.

Step-by-step explanation:

x-15+75=180

x+60=180

x=120.

3 0

3 years ago

A manager records the repair cost for 4 randomly selected TVs. A sample mean of $88.46 and standard deviation of $17.20 are subs

timurjin [86]

Answer:

NO WAY ITS INSANE

Step-by-step explanation:

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3 years ago

Y= 4x + 4 and -0.25x - 2

Yuri [45]

Answer:

.2

Step-by-step explanation:

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3 years ago

Sam wants to meet his friend Beth at a restaurant before they go to the ththeaterThe restaurant is nine kilometers south of the

nata0808 [166]

I suppose the restaurant's coordinates are (0, -9), but it is all relative, unless the coordinates of the restaurant have a y-value 9 less than the coordinates of the theater

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3 years ago