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3 years ago

What is the electron configuration for oxygen with a 2- charge (o2-)?

1 answer:

3 0

Oxygen:
Atomic no. = 8(from periodic table)
⇒1s^2 2s^2 2p^4
But it is O^2-
There are 2 more electrons
=>1s^2 2s^2 2p^6
Voila!

You might be interested in

A pure substance that is present before a reaction but not after Super Confused

never [62]

Explanation:

Pure subsance is a substance that is made up of only one type of particle - each piece is the same throughout.

Being present before the reaction but not after means it's no the same (it couldve evaporated)

4 0

3 years ago

Which of the following would have the highest buffer capacity?

Mrrafil [7]

Answer:

1.25 M HCO₃⁻ / 1.25 M CO₃²⁻

Explanation:

Buffer capacity refers to the amount of a strong acid or base required per liter of the buffer to change its pH by one. This amount is directly related to the concentration of the conjugate acid-base pair in the buffer since the buffer pair neutralizes the strong acid or base.

Thus, the highest buffer capacity is found in the solution that has the highest concentration of the conjugate acid-base pair, which is 1.25 M HCO₃⁻ / 1.25 M CO₃²⁻ .

7 0

3 years ago

A balloon sits in the sunlight causing it to heat up and explode. Which of the following

luda_lava [24]

I think it’s A, the particles of gas inside the ballon move faster and decrease pressure in

6 0

1 year ago

Calculate the volume occupied by 272g

cupoosta [38]

The answer for the following problem is mentioned below.

Therefore volume occupied by methane gas is 184.78 × 10^-3 liters

Explanation:

Given:

mass of methane( $CH_{4}$ ) = 272 grams

pressure (P) = 250 k Pa =250×10^3 Pa

temperature(t) = 54°C =54 + 273 = 327 K

Also given:

R = 8.31JK-1 mol-1 ,

Molar mass of methane( $CH_{4}$ ) = 16.0 grams

We know;

According to the ideal gas equation,

P × V = n × R × T

here,

n = m÷M

n =272 ÷ 16

n = 17 moles

Therefore,

250×10^3 × V = 17 × 8.31 × 327

V = ( 17 × 8.31 × 327 ) ÷ ( 250×10^3 )

V = 184.78 × 10^-3 liters

Therefore volume occupied by methane gas is 184.78 × 10^-3 liters

6 0

3 years ago

A physician has ordered 0.50 mg of atropine, intramuscularly. If atropine were available as 0.25 mg/mL of solution, how many mil

sladkih [1.3K]

If 0.25mg of atropine is in 1mL
so
0.50mg of atropine is in x

$x=\frac{0.5mg*1mL}{0.25mg}=2mL$

6 0

3 years ago