<u>Answer:</u> The volume of hydrogen gas collected over water is 2.13 L
<u>Explanation:</u>
To calculate the number of moles, we use the equation:
![\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}](https://tex.z-dn.net/?f=%5Ctext%7BNumber%20of%20moles%7D%3D%5Cfrac%7B%5Ctext%7BGiven%20mass%7D%7D%7B%5Ctext%7BMolar%20mass%7D%7D)
Given mass of zinc = 5.566 g
Molar mass of zinc = 65.4 g/mol
Putting values in above equation, we get:
![\text{Moles of zinc}=\frac{5.566g}{65.4g/mol}=0.0851mol](https://tex.z-dn.net/?f=%5Ctext%7BMoles%20of%20zinc%7D%3D%5Cfrac%7B5.566g%7D%7B65.4g%2Fmol%7D%3D0.0851mol)
For the given chemical reaction:
![Zn(s)+2HCl(aq.)\rightarrow H_2(g)+ZnCl_2(aq.)](https://tex.z-dn.net/?f=Zn%28s%29%2B2HCl%28aq.%29%5Crightarrow%20H_2%28g%29%2BZnCl_2%28aq.%29)
As, HCl is present in excess. So, it is considered as an excess reagent.
Zinc is considered as a limiting reagent because it limits the formation of product.
By Stoichiometry of the reaction:
1 mole of zinc produces 1 mole of hydrogen gas.
So, 0.0851 moles of zinc will produce =
of hydrogen gas
To calculate the volume of hydrogen gas, we use ideal gas equation, which is:
PV = nRT
where,
P = Pressure of hydrogen gas = Total atmospheric pressure - vapor pressure of water = (752 - 18.65) mmHg = 733.35 mmHg
V = Volume of the hydrogen gas
n = number of moles of gas = 0.0851 moles
R = Gas constant = ![62.3637\text{ L.mmHg }mol^{-1}K^{-1}](https://tex.z-dn.net/?f=62.3637%5Ctext%7B%20L.mmHg%20%7Dmol%5E%7B-1%7DK%5E%7B-1%7D)
T = Temperature of hydrogen gas = ![21^oC=[21+273]K=294K](https://tex.z-dn.net/?f=21%5EoC%3D%5B21%2B273%5DK%3D294K)
Putting values in above equation, we get:
![733.35mmHg\times V=0.0851mol\times 62.3637\text{ L.mmHg }mol^{-1}K^{-1}\times 294K\\\\V=\frac{0.0851\times 62.3637\times 294}{733.35}=2.13L](https://tex.z-dn.net/?f=733.35mmHg%5Ctimes%20V%3D0.0851mol%5Ctimes%2062.3637%5Ctext%7B%20L.mmHg%20%7Dmol%5E%7B-1%7DK%5E%7B-1%7D%5Ctimes%20294K%5C%5C%5C%5CV%3D%5Cfrac%7B0.0851%5Ctimes%2062.3637%5Ctimes%20294%7D%7B733.35%7D%3D2.13L)
Hence, the volume of hydrogen gas collected over water is 2.13 L