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masya89 [10]
3 years ago
7

40 POINTS write a lab report about types of reactions

Chemistry
2 answers:
Masteriza [31]3 years ago
6 0

Answer:

The purpose of this lab was to explore the different types of chemical reactions in this laboratory procedure. The question for this lab is, how does knowing the reactants and products help me classify a chemical reaction.  In this experiment, I made observations of the reactants and the products. I used these observations to write the balanced chemical equations and to classify the reaction it made.

Explanation:

frozen [14]3 years ago
5 0

Answer:

bruh

Explanation:

The purpose of this lab was to explore the different types of chemical reactions in this laboratory procedure. The question for this lab is, how does knowing the reactants and products help me classify a chemical reaction.  In this experiment, I made observations of the reactants and the products. I used these observations to write the balanced chemical equations and to classify the reaction it made.

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Zinc + Hydrochloric Acid → Zinc Chloride and Hydrogen Gas
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Explanation:

because in the right side there is 2 hydrogen( H) and 2 chloride (Cl) to balace them we have to replace 2.

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3 years ago
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According to Newton's Third Law, If one object exerts a force on a second object, the second object exerts a force on the first
blagie [28]

Equal in magnitude and opposite in direction.

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2 years ago
Find the volume of 20g of H₂ at STP<br><br>​
ANEK [815]

Answer:224

Explanation:

We should answer it with Stoichiometry

We say: 20 g H2× (1 mol/ 2g)× ( 22.4 lit/ 1 mol) = 224

Means: we have 20 grams and every 2g H2, equals to 1 mol of it and every 1 mol of H2, equals to 22.4 lit( because of STP)

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6 0
3 years ago
An experiment reveals that 125.0 grams of an unknown metal increases in temperature from 22.0 oC to 43.6 oC upon absorbing 640 j
nydimaria [60]

Answer:

                     Cp  =  0.237 J.g⁻¹.°C⁻¹

Explanation:

                      Amount of energy required by known amount of a substance to raise its temperature by one degree is called specific heat capacity.

The equation used for this problem is as follow,

                                                 Q  =  m Cp ΔT   ----- (1)

Where;

           Q  =  Heat  =  640 J

           m  =  mass  =  125 g

           Cp  =  Specific Heat Capacity  =  <u>??</u>

           ΔT  =  Change in Temperature  =  43.6 °C  -  22 °C  =  21.6 °C

Solving eq. 1 for Cp,

                                Cp  =  Q / m ΔT

Putting values,

                                Cp  =  640 J / (125 g × 21.6 °C)

                                Cp  =  0.237 J.g⁻¹.°C⁻¹

3 0
2 years ago
Which wave has the greatest distance from trough to trough?
mylen [45]

Answer:

a

Explanation:

8 0
2 years ago
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