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Gnom [1K]
3 years ago
7

Calculate the volume occupied by 272g

Chemistry
1 answer:
cupoosta [38]3 years ago
6 0

The answer for the following problem is mentioned below.

<u><em>Therefore volume occupied by methane gas is  184.78 × 10^-3 liters </em></u>

Explanation:

Given:

mass of methane(CH_{4}) = 272 grams

pressure (P) = 250 k Pa =250×10^3 Pa

temperature(t) = 54°C =54 + 273 = 327 K

Also given:

R = 8.31JK-1 mol-1 ,

Molar mass of  methane(CH_{4}) = 16.0​  grams

We know;

According to the ideal gas equation,

<u><em>P × V = n × R × T</em></u>

here,

n = m÷M

n =272 ÷ 16

<u><em>n = 17 moles</em></u>

Therefore,

250×10^3 × V = 17 × 8.31 × 327

V = ( 17 × 8.31 × 327 ) ÷ ( 250×10^3 )

V = 184.78 × 10^-3 liters

<u><em>Therefore volume occupied by methane gas is  184.78 × 10^-3 liters </em></u>

<u><em></em></u>

<u><em></em></u>

<u><em></em></u>

<u><em></em></u>

<u><em></em></u>

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What is the specific latent heat of fusion of ice if it takes 863 kJ to convert 4.6 kg of ice into water at 0 C?
charle [14.2K]

Answer:

The correct answer is 187.7 J/Jg.

Explanation:

The formula for finding the specific heat of fusion is,  

Specific heat of fusion = Q/m

Here Q is the heat energy added, signified in kJ, and m is the mass of the object in kg.  

Based on the given information, the heat energy added or Q is 869 kJ and the mass of the ice is 4.6 Kg

Now putting the values in the formula we get,  

Specific heat of fusion = Q/m

Specific heat of fusion = 863 kJ / 4.6 Kg = 187.7 J/Kg

5 0
3 years ago
What volume of 0.160 m li2s solution is required to completely react with 130 ml of 0.160 m co no3 2?
Over [174]
The  volume  of  0.160    m   Li2S  solution  required  to  completely  react  with  130 ml  of 0.160  CO(NO3)2  is calculated   as  below

write the  reacting  equation

Co(NO3)2 +  Li2S = 2LiNO3  +  COS

find the    moles  of CO(NO3)2  = molarity  x  volume

=  130 ml  x  0.160=20.8  moles

since the reacting moles between CO(NO3)2  to LiS  is   1:1  the  moles of LiS  is  also  20.8  moles

volume  of Lis  is  therefore =  moles of Lis/ molarity  of LiS

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3 0
3 years ago
pyrite is a mineral composed of 46.5 mass % iron and 53.5 mass % sulfur. determine the empirical formula for calcocite.
padilas [110]

The empirical formula for pyrite is FeS2.

HOW TO CALCULATE EMPIRICAL FORMULA:

  • The empirical formula represents the simplest whole number ratio of constituents element of a compound. The empirical formula of pyrite can be calculated as follows:

46.5 mass % Fe = 46.5g of Fe

53.5 mass % S = 53.5g of S

  • Next, we divide each element's mass value by its molar mass

Fe = 46.5g ÷ 56g/mol = 0.83mol

S = 53.5g ÷ 32g/mol = 1.67mol

  • Next, we divide each mole value by the smallest (0.83mol)

Fe = 0.83mol ÷ 0.83 = 1

S = 1.67mol ÷ 0.83 = 2.014

Approximately, the ratio of Fe to S is 1:2. Therefore, the empirical formula of pyrite is FeS2.

Learn more at: brainly.com/question/14044066?referrer=searchResults

3 0
1 year ago
For which of the following processes would you expect there to be an increase entropy
adoni [48]
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Answer:

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Explanation:

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