Answer:
A
Step-by-step explanation:
Answer:
hello your question is incomplete here is the complete question
Use cylindrical coordinates Find the volume of the solid that lies within both the cylinder x^2 + y^2=16 and the sphere x^2 + y^2 + Z^2= 81
Answer : ![\frac{4 \pi }{3} [729 - 65\sqrt{65} ]](https://tex.z-dn.net/?f=%5Cfrac%7B4%20%5Cpi%20%7D%7B3%7D%20%5B729%20-%2065%5Csqrt%7B65%7D%20%5D)
Step-by-step explanation:
The given data
cylinder = x^2 + y^2 = 16
sphere = x^2 + y^2 +z^2 = 81
from the given data the solid is symmetric around the xy plane hence we will calculate half the solid volume above the plane then multiply the sesult by 2
Note : we are restricting our attention to the cylinder x^2 + y^2 = 16 and also finding the volume inside the sphere which gives bound on the z-coordinate as well
the r parameter goes from 0 to 4
ATTACHED IS THE REMAINING PART OF THE SOLUTION
showing the integration
To evaluate an algebraic expression, you have to substitute a number for each variable and perform the arithmetic operations. In the example above, the variable x is equal to 6 since 6 + 6 = 12. If we know the value of our variables, we can replace the variables with their values and then evaluate the expression.
Remember that the angles of a triangle is 180 so:
(7x+8) + (5x+2) + (7x-1) = 180
7x+8+5x+2+7x-1=180
7x+5x+7x=180-8-2+1
19x=171
X= 171/19
X=9
Therefore x=9
Answer: The correct answer is the second one
Step-by-step explanation: