Given:
Stopping distance range is d = (65, 70) ft.
The stopping distance, d, obeys this formula.
d = v²/(2μg)
where
v = speed of the vehicle
μ = 0.8, coefficient of static friction under good road conditions
g = acceleration due to gravity, 32.2 ft/s²
Therefore
v = √(2*0.8*32.2*d) = 7.178√d
Test d = 65 ft.
v = 7.178√(65) = 57.87 ft/s = (57.87/88)*60 = 39.5 mph
Test d = 70 ft.
v = 7.178√(70) = 60.05 ft/s = 40.9 mph
To be safe, the lower speed of 39.5 mph is preferred.
Answer: 40 mph
Answer:
A
A. Energy is lost when machines don't work right.
That is potential energy.
Fundamental frequency,
f=v2l=T/μ−−−−√2l
=(50)/0.1×10−3/10−22×0.6−−−−−−−−−−−−−−−−−−−√
=58.96Hz
Let, n th harmonic is the hightest frequency, then
(58.93)n = 20000
∴N=339.38
Hence, 339 is the highest frequency.
∴fmax=(339)(58.93)Hz=19977Hz.
<h3>
What is frequency?</h3>
In physics, frequency is the number of waves that pass a given point in a unit of time as well as the number of cycles or vibrations that a body in periodic motion experiences in a unit of time. After moving through a sequence of situations or locations and then returning to its initial position, a body in periodic motion is said to have experienced one cycle or one vibration. See also simple harmonic motion and angular velocity.
learn more about frequency refer:
brainly.com/question/254161
#SPJ4
Answer:
M_Train>> m_car a_train <a_car
Explanation:
To start the movement of the train or the car, the motorcycle applies a force on the wheels, which starts the acceleration in the case of the train, it has a much greater mass than that of the car, for which to obtain the same acceleration necessary a much greater force
a = F / m
as the mass of the train is greater than that of the car.
a_train <a_car
Something similar happens when the vehicles stop, the engine stops applying force forward and the brakes apply a force backward that creates a negative acceleration that slows down, again as the mass of the train is much greater than the of the car its negative acceleration is much less.
It is good to clarify that to compensate for this the trains have a braking system on all wheels
