Ask question

Ask question

All categories

Svetradugi [14.3K]

3 years ago

14

A glass of water sits on a scale. The scale reads 4.78 N. A steel bolt weighs 2.07 N. The density of steel is 7.86 g/cm3. We tie

the bolt to a string and lower the bolt into the glass of water so that the bolt is fully submerged in the water but is not touching the bottom or side of the glass.

1 answer:

miv72 [106K]3 years ago

4 0

Answer:

The weight of water weight is 5.043 N.

Explanation:

Given that,

Force = 4.78 N

Weight of steel bolt = 2.07 N

Density of steel = 7.86 g/cm³

Suppose determine how much does the glass of water weight.

We need to calculate the volume of bolt

Using formula of density

$\rho_{b}=\dfrac{m}{V}$

$V=\dfrac{m}{\rho_{b}}$

Put the value into the formula

$V=\dfrac{2.07}{9.8\times7860}$

$V=2.6873\times10^{-5}\ m^3$

We need to calculate the force on bolt

Using buoyant force

$F=\rho gV$

Put the value into the formula

$F=1000\times9.8\times2.6873\times10^{-5}$

$F=0.263\ N$

We need to calculate the new weight of glass of water

Using formula for weight of glass of water

$W'_{w}=W_{w}+F_{b}$

Put the value into the formula

$W=4.78+0.263$

$W=5.043\ N$

Hence, The weight of water weight is 5.043 N.

You might be interested in

To which group/family does each of these belong? A. Sulfur _________ B. Sodium _________ C. Argon _________ D. Silicon _________

ArbitrLikvidat [17]

Answer:

A. Sulfur _________ group 16 chalcogens

B. Sodium _________ group 1 alkali metals

C. Argon _________ group 18 noble gases

D. Silicon _________ group 14 carbon family

E. Chlorine _________ group 17 halogens

F. Phosphorus_________ group 15 pnicogens

7 0

2 years ago

What is it's potential energy when it is 1000m above the ground

ycow [4]

Explanation:

stresses within itself or other factors. since 1000m is above the ground, it would rely on gravity, such as; " what goes up must come down," the gravity is present because it is above ground level, example, a mud slide on a small island, needs h2o to become heavier to collapse...

5 0

3 years ago

Juan is making ice tea. When he adds ice to the tea, why does the tea cool down?

Tresset [83]

Answer: because the ice was cold, and it melted in the tea. So the tea is now cooler.

Explanation:

4 0

3 years ago

A bucket of water with total mass 23 kg is attached to a rope, which in turn, is wound around a 0.050-m radius cylinder at the t

aliina [53]

The question seems a bit incomplete. The question should be as follow:

A bucket of water with total mass 23 kg is attached to a rope, which in turn, is wound around a 0.050-m radius cylinder at the top of a well. A crank with a turning radius of 0.25 m is attached to the end of the cylinder. What minimum force directed perpendicular to the crank handle is required to just raise the bucket? (Assume the rope's mass is negligible, that cylinder turns on frictionless bearings, and that g= 9.8 m/s2.)

Answer:

45.08N

Explanation:

The question involves moment topic. Note that the equation of moment, M is

Moment, M = Force, F x Perpendicular distance from the turning point, d

M = F x d

Moment involves turning movement along the pivot. in this case, we have 2 pivots. The first one the attached near the rope, while the other is the crank.

To raise the bucket, minimum force required must be able to provide at least the same moment as the moment due to the bucket of water. i.e.

Moment due to bucket = moment due to force on the crank

First find the moment due to bucket,

Mb = F (weight) x d (radius of cylinder on top of well)

= (23 x 9.8) x 0.05

= 11.27 Nm

Next, Find the moment due to force on the crank. Note that the force is the minimum required force for this equation.

Mc = F (min Force) x d (radius of crank)

= F x 0.25 = 0.25F

Now we get a simple equation of

11.27 = 0.25F

Using Algebra, we'll get the minimum Force, F:

F = 11.27 / 0.25

= 45.08 N

4 0

4 years ago

Read 2 more answers

A dinner plate falls vertically to the floor and breaks up into three pieces, which slide horizontally along the floor. Immediat

N76 [4]

Answer:

p_k=\sqrt{p_x^2+p_y^2}}

Explanation:

Apply the momentum in each direction knowing that the impact is at the same time for the pieces so

$p_x=m_1*v_1$

$p_x=200g*2.0m/s=0.4kgm/s$

$p_y=m_2*v_2$

$p_y=235g*1.5m/s=0.3525kgm/s$

So the momentum in the other piece can be find knowing that

$p_x^2+p_y^2=p_k^2$

So:

$p_k=\sqrt{p_x^2+p_y^2}}$

$p_k=\sqrt{0.4^2+0.3525^2}}=\sqrt{0.2842 kg^2*m^2/s^2}$

$p_k=0.5331kg*m/s$

To find the velocity knowing the mass

$p_k=m_k*v_k$

$v_k=\frac{p_k}{m_k}=\frac{0.5331 kg*m/s}{0.10kg}$

$v_k=5.331 m/s$

4 0

3 years ago