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Svetradugi [14.3K]
3 years ago
14

A glass of water sits on a scale. The scale reads 4.78 N. A steel bolt weighs 2.07 N. The density of steel is 7.86 g/cm3. We tie

the bolt to a string and lower the bolt into the glass of water so that the bolt is fully submerged in the water but is not touching the bottom or side of the glass.
Physics
1 answer:
miv72 [106K]3 years ago
4 0

Answer:

The weight of water weight is 5.043 N.

Explanation:

Given that,

Force = 4.78 N

Weight of steel bolt = 2.07 N

Density of steel = 7.86 g/cm³

Suppose determine how much does the glass of water weight.

We need to calculate the volume of bolt

Using formula of density

\rho_{b}=\dfrac{m}{V}

V=\dfrac{m}{\rho_{b}}

Put the value into the formula

V=\dfrac{2.07}{9.8\times7860}

V=2.6873\times10^{-5}\ m^3

We need to calculate the force on bolt

Using buoyant force

F=\rho gV

Put the value into the formula

F=1000\times9.8\times2.6873\times10^{-5}

F=0.263\ N

We need to calculate the new weight of glass of water

Using formula for weight of glass of water

W'_{w}=W_{w}+F_{b}

Put the value into the formula

W=4.78+0.263

W=5.043\ N

Hence, The weight of water weight is 5.043 N.

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Acceleration = (2,000 m/s north) / (40 seconds)

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[1] The assembly starts from rest and reaches an angular speed of 150 rev/min under the action of a 20-N force T applied to the
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Explanation:

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You lift a 10-kg box to a height of 1m. How much work do you do on the box when you lift it from the ground? (g= 9.81 m/s2)
Andreyy89

Answer:

98.1 Joule

Explanation:

Solution,

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F_{engine}=425+840=1265 N

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