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RSB [31]
3 years ago
14

What is the value of the expression?

Mathematics
1 answer:
Romashka-Z-Leto [24]3 years ago
7 0

Answer: 867

Step-by-step explanation:

You subtract what is in the parentheses then add them together

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Jannet saved 22 dollars one month and 39 dollars the next month. She wants to by a bicycle that costs $ 100. About how much more
coldgirl [10]
22 dollars + 39 dollars = 61 dollars

100-61= 39 dollars. She needs $39 more
7 0
3 years ago
Describe the steps needed to solve 8x-12y=-3 for y.
Sholpan [36]

Answer:

y = (2 x)/3 + 1/4

Step-by-step explanation:

Solve for y:

8 x - 12 y = -3

Subtract 8 x from both sides:

-12 y = -8 x - 3

Divide both sides by -12:

Answer: y = (2 x)/3 + 1/4

4 0
3 years ago
Given that f(x) = 7x^2 − 84 = 0, find x.
jasenka [17]

Answer:

x = 3.464

Step-by-step explanation:

7x^2 - 84 = 0

7x^2 = 84

x^2 = 12

x= 3.464

8 0
3 years ago
Sandra's scores on the first 4 tests were 87%, 92%, 76%,and 89%. What is the minimum score she needs to make on the fifth test s
sergejj [24]

Answer:

Sandra need to score at least <u>56%</u> in her fifth test so that her average is 80%.

Step-by-step explanation:

Given:

First 4 test scores = 87%, 92%, 76%,89%

Average targeted = 80%

We need to find the minimum score she needs to make on fifth test to achieve average of at least 80%.

Solution:

Let the minimum score she needs to make in fifth test be 'x'.

Total number of test = 5

Now we know that;

Average is equal to sum of all the scores in the test divided by number of test.

framing in equation form we get;

\frac{87+92+76+89+x}{5}=80

Multiplying both side by 5 we get;

\frac{344+x}{5}\times 5=80\times 5\\\\344+x=400

Subtracting both side by 344 we get;

344+x-344=400-344\\\\x=56\%

Hence Sandra need to score at least <u>56%</u> in her fifth test so that her average is 80%.

5 0
3 years ago
2) Dada a equação x2 – 4x – 12, faça o que se pede.
alexandr1967 [171]

Answer:

a) x1 = 6 and x2 = -2

b) -2

Step-by-step explanation:

a)

To find the roots of the quadratic equation, we can use the Bhaskara's formula:

Delta = b^2 - 4ac

Delta = (-4)^2 - 4*1*(-12) = 64

sqrt(Delta) = 8

x1 = (-b + sqrt(Delta)) / 2a

x1 = (4 + 8) / 2

x1 = 6

x2 = (-b - sqrt(Delta)) / 2a

x2 = (4 - 8) / 2

x2 = -2

b)

The roots are 6 and -2, so the smaller root is -2

4 0
3 years ago
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