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3 years ago

Shannon uses 30 inches of ribbon to make one bow how many feet of ribbon are needed to make 10 bows

2 answers:

6 0

First, we need to calculate the amount of ribbon in inches, and then convert it into feet.

Since 30 inches of ribbon is used in one bow, to make 10 bows, we need multiply:

30 x 10 = 300

Now, we need to convert the inches to feet.

300 in = 25 ft

Our answer is 25 ft of ribbon.

Hope this helped!

love history [14]3 years ago

4 0

Well you need to divide them then after that multiply the number you got from the 10 and 30 then subtract the number that you got from the 10 and 30. And then y'all get you answer.

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Identify the polygon with vertices A(5,0), B(2,4), C(−2,1), and D(1,−3), and then find the perimeter and area of the polygon. HE

inn [45]

Answer:

Part 1) The polygon is a square

Part 2) The perimeter is equal to $20\ units$

Part 3) The area is equal to $25\ units^{2}$

Step-by-step explanation:

we have

$A(5,0), B(2,4), C(-2,1),D(1,-3)$

Plot the points

see the attached figure

we know that

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Find the distance AB

$A(5,0),B(2,4)$

substitute in the formula

$d=\sqrt{(4-0)^{2}+(2-5)^{2}}$

$d=\sqrt{(4)^{2}+(-3)^{2}}$

$d=\sqrt{25}$

$AB=5\ units$

Find the distance BC

$B(2,4), C(-2,1)$

substitute in the formula

$d=\sqrt{(1-4)^{2}+(-2-2)^{2}}$

$d=\sqrt{(-3)^{2}+(-4)^{2}}$

$d=\sqrt{25}$

$BC=5\ units$

Find the distance CD

$C(-2,1),D(1,-3)$

substitute in the formula

$d=\sqrt{(-3-1)^{2}+(1+2)^{2}}$

$d=\sqrt{(-4)^{2}+(3)^{2}}$

$d=\sqrt{25}$

$CD=5\ units$

Find the distance AD

$A(5,0),D(1,-3)$

substitute in the formula

$d=\sqrt{(-3-0)^{2}+(1-5)^{2}}$

$d=\sqrt{(-3)^{2}+(-4)^{2}}$

$d=\sqrt{25}$

$AD=5\ units$

we have that

AB=BC=CD=AD

Find the distance BD (diagonal)

$B(2,4),D(1,-3)$

substitute in the formula

$d=\sqrt{(-3-4)^{2}+(1-2)^{2}}$

$d=\sqrt{(-7)^{2}+(-1)^{2}}$

$BD=\sqrt{50}\ units$

Verify if the polygon is a square

If the triangle BDA is a right triangle, then the polygon is a square

Applying the Pythagoras theorem

$BD^{2}=AD^{2}+AB^{2}$

substitute

$(\sqrt{50})^{2}=5^{2}+5^{2}$

$50=50$ -----> is true

The triangle BDA is a right triangle

therefore

The polygon is a square

Find the Area of the polygon

The area of a square is equal to

$A=b^{2}$

we have

$b=5\ units$

$A=5^{2}=25\ units^{2}$

Find the perimeter of the polygon

The perimeter of a square is equal to

$P=4b$

we have

$b=5\ units$

$P=4(5)=20\ units$

6 0

3 years ago

Help plz !!!!!!!!!!!!!!!!! These are so hard

OlgaM077 [116]

Answer:

$m=\frac{4}{9}$

Step-by-step explanation:

Using the slope formula:

$m=\frac{1+7}{10+8}=\frac{8}{18}=\frac{4}{9}$

6 0

3 years ago

1. Which would be a more helpful for solving the system: adding the two equations or subtracting

ira [324]

Answer:

1) Subtracting one from the other

2) x = 0.375 and y = 0.125

Step-by-step explanation:

Equation 1 :

$\frac{2x+1}{2y}=7\\\\$

Equation 2:

$\frac{6x-1}{2y}=5$

To solve these equations by the Elimination method we multiply equation 1 with 6 and multiply equation 2 with 2 so now,

$\frac{2x+1}{2y} =7\\\\2x+1=14y\\\\Multiplying\ Equation\ 1\ with\ 6\\\\12x+6=84y$

Now for the second equation:

$\frac{6x-1}{2y}=5\\\\6x-1=10y\\\\Multiplying\ equation\ 2\ with\ 2 \\\\12x-2=20y$

Now subtracting equation 2 from equation 1

$12x+6=84y\\\\12x-2=20y\\\\Subtracting\ leads\ to\\12x-12x+6-(-2)=84y-20y\\0+8=64y\\8=64y\\8/64=y\\0.125=y$

now insert this value of y into any equation

lets insert it into equation 1

$\frac{2x+1}{2y} =7\\\\2x+1=14y\\2x+1=14(0.125)\\2x+1=1.75\\2x=1.75-1\\2x=0.75\\x=0.75/2\\x-0.375$

5 0

3 years ago

A 1970 comic book has appreciated 7% per year and originally sold for $0.35. What will the comic book be worth in 2017?

omeli [17]

You tell me if this makes sense to you.

It's 47 years from 1970 to 2017 so you would need to multiply 7% by the 47 years.

So: 0.07x47= 3.29

Now you should add your new price to your original price: $3.29+$0.35= 3.64

So it should cost $3.64 now. Yes that does seem kind of low but that's how you do it.

I hope this helps :)

6 0

4 years ago

What are the next three terms in the pattern 2, 6, 18, 54, ...?

castortr0y [4]

Answer:

OPTION B: 162, 486, 1458

Step-by-step explanation:

The given sequence is 2, 6, 18, 54, . . .

It is a geometric sequence and the common difference is 3.

The general form of a geometric sequence is: a, ar, ar², ar³, . . .

Here a = 2 and r = 3.

$n^{th}$ term of a Geometric progression is $ar^{n - 1}$ .