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3 years ago

Hello can you please help me posted picture of question

Mathematics

1 answer:

White raven [17]3 years ago

3 0

Correct answer will be option A.

Two events are independent if the occurring of one event does not impact the occurring of the other event.

So this means, the knowledge of one event is having no impact on the probability of occurrence of the second event. Thus option A is correct

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A trough has ends shaped like isosceles triangles, with width 2 m and height 5 m, and the trough is 18 m long. Water is being pu

fenix001 [56]

9514 1404 393

Answer:

5/9 m/min

Step-by-step explanation:

The depth of the water is 2/5 of the depth of the trough, so the width of the surface will be 2/5 of the width of the trough:

2/5 × 2 m = 4/5 m

Then the surface area of the water is ...

A = LW = (18 m)(4/5 m) = 14.4 m²

The rate of change of height multiplied by the area gives the rate of change of volume:

8 m³/min = (14.4 m²)(h')

h' = (8 m³/min)/(14.4 m²) = 5/9 m/min

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3 years ago

Lilly bought stock at $83.60. The next day, the price increased by $15.35. Then this price changed by $-2.15.Wgat was the final

rodikova [14]

The final stock price would be $96.8

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2 years ago

Is negative 2 greater than, less than or equal to 1/2?

Mice21 [21]

Answer:

Less than :)

Step-by-step explanation:

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3 years ago

Read 2 more answers

Hlp me solve this k/2+1-1k=-2k

Fofino [41]

Answer:k2+1−1k=−2kAlso Plz give me a Thanks PLZ

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3 years ago

Hey how do you get from standard form to vertex form?

vlabodo [156]

Explanation:

Conversion of a quadratic equation from standard form to vertex form is done by completing the square method.

Assume the quadratic equation to be $\mathbf{ax^{2}+bx+c=0}$ where x is the variable.

Completing the square method is as follows:

send the constant term to other side of equal $\mathbf{ax^{2}+bx=-c}$
divide the whole equation be coefficient of $\mathbf{x^{2}}$ , this will give $\mathbf{x^{2}+\frac{b}{a}x=- \frac{c}{a}}$
add $\mathbf{(\frac{b}{2a})^{2}}$ to both side of equality $\mathbf{x^{2}+2\times\frac{b}{2a}x+\frac{b}{2a}^{2}=-\frac{c}{a}+\frac{b}{2a}^{2}}$
Make one fraction on the right side and compress the expression on the left side $\mathbf{(x+\frac{b}{2a})^{2}=\frac{b^{2}-4ac}{4a^{2}}}$
rearrange the terms will give the vertex form of standard quadratic equation $\mathbf{a(x+\frac{b}{2a})^{2}-\frac{b^{2}-4ac}{4a}=0}$

Follow the above procedure will give the vertex form.

(NOTE : you must know that $\mathbf{(x+a)^{2}=x^{2}+2ax+a^{2}}$ . Use this equation in transforming the equation from step 3 to step 4)

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3 years ago