How do you solve 1-cos2x/cosx •cscx=tanx

1 answer:

6 0

(1-cos^2x/cosx)*cosecx
(sin^2x/cosx)*sinx (where 1-cos^2x=sin^2x) and 1/cscx=sinx

sinx/cosx=tanx(divide by sinx)
hence proved

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