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3 years ago

The acceleration due to gravity on Earth is 9.80 m/s2. An African elephant can have a mass up to 6,050 kg. What is its weight?

1 answer:

3 0

The weight on earth is equal to m*g, where m is the mass and g is the gravitational force. 6050 (m) * 9.8 (g) = 59290 Newtons.

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A circuit consists of a 171- resistor and a 0.158-H inductor. These two elements are connected in series across a generator that

kotykmax [81]

Answer:

a ) I= 1.635-i0.0021 b) ∅= -0.074

Explanation:

a) reactive impeadance= 2πfL

=2(3.14)(147)(0.158)

=145.86 Ω

Z= 171+j145.86

I=V/Z

I=278/(171+j145.86)

I= 1.635-i0.0021

b) ∅=inv.tan (-0.0021/1.635)

∅=-0.074

6 0

3 years ago

___is when a force is exerted on an object and the object moves a distance in the direction of the force.

defon

The correct option is A) work.

Work is said to be done by a force when a force is exerted on an object and the the object on which the force is exerted moves in the direction of the force.

The amount of work done is given by the product of the force and the displacement made by the object.

Option (B) is incorrect, since Watt is the unit of power.

Option (C) is wrong, since joule is the unit of work or energy.

Option (D) is wrong, since power is the rate at which work is done.

5 0

3 years ago

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A 2000 kg car moves along a horizontal road at speed vo

cluponka [151]

Answer:

The shortest possible stopping distance of the car is 175.319 meters.

Explanation:

In this case we see that driver use the brakes to stop the car by means of kinetic friction force. Deceleration of the car is directly proportional to kinetic friction coefficient and can be determined by Second Newton's Law:

$\Sigma F_{x} = -\mu_{k}\cdot N = m \cdot a$ (Eq. 1)

$\Sigma F_{y} = N-m\cdot g = 0$ (Eq. 2)

After quick handling, we get that deceleration experimented by the car is equal to:

$a = -\mu_{k}\cdot g$ (Eq. 3)

Where:

$a$ - Deceleration of the car, measured in meters per square second.

$\mu_{k}$ - Kinetic coefficient of friction, dimensionless.

$g$ - Gravitational acceleration, measured in meters per square second.

If we know that $\mu_{k} = 0.0735$ and $g = 9.807\,\frac{m}{s^{2}}$ , then deceleration of the car is:

$a = -(0.0735)\cdot (9.807\,\frac{m}{s^{2}} )$

$a = -0.721\,\frac{m}{s^{2}}$

The stopping distance of the car ( $\Delta s$ ), measured in meters, is determined from the following kinematic expression:

$\Delta s = \frac{v^{2}-v_{o}^{2}}{2\cdot a}$ (Eq. 4)

Where:

$v_{o}$ - Initial speed of the car, measured in meters per second.

$v$ - Final speed of the car, measured in meters per second.

If we know that $v_{o} = 15.9\,\frac{m}{s}$ , $v = 0\,\frac{m}{s}$ and $a = -0.721\,\frac{m}{s^{2}}$ , stopping distance of the car is:

$\Delta s = \frac{\left(0\,\frac{m}{s} \right)^{2}-\left(15.9\,\frac{m}{s} \right)^{2}}{2\cdot \left(-0.721\,\frac{m}{s^{2}} \right)}$

$\Delta s = 175.319\,m$

The shortest possible stopping distance of the car is 175.319 meters.

8 0

3 years ago

One difference between a fundamental niche and a realized niche is that ___

forsale [732]

A fundamental niche can be defined as the range of environmental conditions in which each of the species survives. The realized niche can be termed as the range of environmental conditions in which a species is really found.

8 0

3 years ago

Read 2 more answers

What is the speed of a wave with a wavelength of 0.60 m and frequency of 240 Hz

kakasveta [241]

Answer:

it would be 34433.555

Explanation:

5 0

3 years ago