Answer:
<h3>The answer is 0.115 mL</h3>
Explanation:
The volume of a substance when given the density and mass can be found by using the formula
From the question
mass = 10 g
density = 87 g/ml
We have
We have the final answer as
<h3>0.115 mL</h3>
Hope this helps you
Answer:
35 m
Explanation:
Given :
The distance of the path from the ground to the tree limb = 50 m
The angle between the path of flight of the bird towards the tree limb and the ground = 45 degrees
Therefore we can determine the height above which the bird perched above the ground by using the rules of the trigonometric ratios as;
We know that ,
= 35
Therefore, the bird perched on the tree limb at a height of 35 m.
Answer:
k = 1 700.7 N/m
v0 = 9.8 m/s^2
Explanation:
Hello!
We can answer this question using conservation of energy.
The potential energy of the spring (PS) will transform to kinetic energy (KE) of the ball, and eventually, when the velocity of the ball is zero, all that energy will be potential gravitational (PG) energy.
When the kinetic energy of the ball is zero, that is, when it has reached its maximum heigh, all the potential energy of the spring will be equal to the potential energy of the gravitational field.
PS = (1/2) k x^2 <em>where x is the compresion or elongation of the spring</em>
PG = mgh
a)
Since energy must be conserved and we are neglecting any energy loss:
PS = PG
Solving for k
k = (2mgh)/(x^2) = ( 2 * 1.7 * 9.81 * 4.9 Nm)/(0.31^2 m^2)
k = 1 700.7 N/m
b)
Since the potential energy of the spring transfors to kinetic energy of the ball we have that:
PS = KE
that is:
(1/2) k x^2 = (1/2) m v0^2
Solving for v0
v0 = x √(k/m) = (0.31 m ) √( 1 700.7 N/m / 1.7kg)
v0 = 9.8 m/s^2
Answer:
0.9999986*c
Explanation:
The ship would travel 2.54*10^7 light years, which means that at a speed close to the speed of light the trip would take 2.54*10^7 years from the point of view of an observer on Earth. However from the point of view of a passenger of that ship it will take only 70 years if the speed is close enough to the speed of light.
Where
Δt is the travel time as seen by a passenger
Δt' is the travel time as seen by someone on Earth
v is the speed of the ship
c is the speed of light in vacuum
We can replace the fraction v/c with x
It would need to travel at 0.9999986*c
You said 2 revolutions every 0.08 seconds
1 revolution = 2pi radians.
A). The 'unit rate' is (2 rev) x (2pi / 0.08 sec) = 50pi radians/sec. =
157.1 radians per sec (rounded)
B). Radius of the wheel = 30 cm
Circumference = 2pi R = 60pi cm = 188.5 cm (rounded)
Rotation speed = 2 revs per 0.08 sec
Linear speed = 2 x 60pi cm per 0.08 sec
(120pi cm) / (0.08 sec) = 47.12 meters per sec
C). Frequency = (revs) per second
= (2) / (0.08 sec) = 25 per second .
