For a standing wave on a string, the wavelength is equal to twice the length of the string:
![\lambda=2 L](https://tex.z-dn.net/?f=%5Clambda%3D2%20L)
In our problem, L=50.0 cm=0.50 m, therefore the wavelength of the wave is
![\lambda = 2 \cdot 0.50 m = 1.00 m](https://tex.z-dn.net/?f=%5Clambda%20%3D%202%20%5Ccdot%200.50%20m%20%3D%201.00%20m)
And the speed of the wave is given by the product between the frequency and the wavelength of the wave:
The point of contact the path difference is zero but one of the interfering ray is reflected so the effective path difference becomes λ/2 thus the condition of minimum intensity is created in the center.
Answer:
The correct option is;
How loud or soft the sound is
Explanation:
The loudness of a sound wave is given by the amount of energy that the pressure wave carries and it is measured in decibels (dB) which is the relative intensity of the pressure wave of a sound to the standard pressure
A loud sound has a high amplitude and a soft sound has a low amplitude, such that as the amplitude of the sound is increased, due to increased energy input, the sound becomes louder, and as the amplitude of the sound is decreased due to reduced energy input, the sound becomes softer.
Answer:
Seriously I have no idea. I need help with my homework.
Explanation:
I really need help with my homework. Sorry