Answer:
The mass rate of the cooling water required is: 
Explanation:
First, write the energy balance for the condensator: The energy that enters to the equipment is the same that goes out from it; consider that there is no heat transfer to the surroundings and kinetic and potential energy changes are despreciable.
Where w refers to the cooling water and s to the steam flow. Reorganizing,
Write the difference of enthalpy for water as Cp (Tout-Tin):
This equation will let us to calculate the mass rate required. Now, let's get the enthalpy and Cp data. The enthalpies can be read from the steam tables (I attach the tables I used). According to that, 
and 
can be calculated as:
.
The Cp of water at 25ºC (which is the expected average temperature for water) is: 4.176 
. If the average temperature is actually different, it won't mean a considerable mistake. Also we know that 
, so let's work with the limit case, which is 
to calculate the minimum cooling water mass rate required (A higher one will give a lower temperature difference as a result). Finally, replace data:
Looks like something went wrong while editing this question
The question needs to be between 20 and 5000 characters
Answer:
a) three times greater
Explanation:
Remember the heat capacity is the necessary heat to increase the temperature 1 ºC to an specific mass of the substance, in this case since the water and the metal have the same mass, is easier to compare just the neccesary heat.
Since water increases 20 ºC and the metal 60 ºC, it was neccesary 3 times of the quantity of heat to the same amount of mass of the two different susbtances.
Hope it was useful
A=v/t
So therefore 75/0.050= acceleration
So the answer is a= 1500 metres per second per second
