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Novosadov [1.4K]
3 years ago
15

Which constellation is marked by a W or M? a. Cassiopeia b. Draco c. Ursa Minor d. Ursa Major

Physics
2 answers:
yuradex [85]3 years ago
8 0

Answer:

Ursa Minor Constellation

Explanation:

Ursa Minor constellation lies in the northern sky. The constellation's name means “the smaller bear,” or “the lesser bear,” in Latin. The Great Bear constellation is represented by its larger neighbor Ursa Major.

Anestetic [448]3 years ago
6 0

I believe it is the Cassiopeia. It is visible during winter in the early part of the night. It look like a distorted letter W or M.

I am not very sure of it though, I apologize if this is not what you meant.

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Density of water is 1000kg/m3. Find out the amount of mass of 5m3 water​
Licemer1 [7]

Answer:

5000 m³

Explanation:

density = mass / volume

mass = density × volume

mass = 1000 × 5

mass = 5000 ( kg )

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3 years ago
Which graph illustrates constant speed and velocity?
boyakko [2]

The correct graph is <u>D</u>.

The graph <em>A</em> is a straight line sloping downwards and it shows that the speed of the body is decreasing at a constant rate. Therefore, this s a graph of a body that is under a constant deceleration.

The graph B is a straight line which slopes upwards. Hence the graph shows that the speed of the body increases at a constant rate. Therefore, this is a graph of a body that is accelerating at a constant rate.

The graph C is curved line, which curves upwards. The slope of the curve increases with time. This is therefore, a graph of a body which is under increasing acceleration.

The graph D, however is a straight line parallel to the time axis. The speed of the body has the same value at all times. Therefore, Graph D is the graph which shows the motion of a body with constant speed.

8 0
3 years ago
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Elodia [21]
You have been given the storm's velocity.
7 0
3 years ago
The acceleration due to gravity on the surface of Jupiter is about 2.5 times the acceleration due to gravity on Earth’s surface.
melisa1 [442]
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When responding to sound, the human eardrum vibrates about its equilibrium position. Suppose an eardrum is vibrating with an amp
Paraphin [41]

Answer:

796.18 Hz

Explanation:

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Therefore,

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make f the subject of the equation

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From the question,

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Constant: 3.14.

Substitute these values into equation 2

f = 3.6×10⁻³/( 7.2×10⁻⁷×2×3.14)

f = 796.18 Hz

6 0
3 years ago
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