Answer:
5.59
Explanation:
50 meters in 10 seconds is 11.18, which is an easy way to remember. Just divided by 2
Answer:
Work done = 422.45 kJ
Explanation:
given,
weight of equipment = 6 kN
coefficient of kinetic friction = 0.05
distance up to which it is pulled = 1000 m
constant acceleration = 0.2 m/s²
Work done by the camper = ?
actual acceleration acting a'
m a = m a' - μ mg
a' = a + μ g
a' = 0.2 + 0.05 x 9.8
a' = 0.69 m/s²
Work done = Force x distance
F = m a'

F = 422.44897 N
Work done = F x d
Work done = 422.44897 x 1000
Work done = 422449 J
Work done = 422.45 kJ
Answer:
x₂=0.44m
Explanation:
First, we calculate the length the spring is stretch when the first block is hung from it:

Now, since the stretched spring is in equilibrium, we have that the spring restoring force must be equal to the weight of the block:

Solving for the spring constant k, we get:

Next, we use the same relationship, but for the second block, to find the value of the stretched length:

Finally, we sum this to the unstretched length to obtain the length of the spring:

In words, the length of the spring when the second block is hung from it, is 0.44m.
Answer: Both Technician A and B are right.
Explanation:
Both Technicians are correct. when a valve remains open as it approaches the TDC(top dead center), they piston may strike the valve which would result to damage of the engine. Same applies when it is open as it approaches the top dead center as a valve train damage may occur. As the driven train is responsible for providing power to the wheels from the engine block.
Answer uhhh
Explanation:
WHAT???
EVER!!!!!!!!
HAHAHAHAH