S Suppose you wish to fabricate a uniform wire from a mass m of a metal with density rhom and resistivity rho. If the wire is to
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Answer:
Work done = 422.45 kJ
Explanation:
given,
weight of equipment = 6 kN
coefficient of kinetic friction = 0.05
distance up to which it is pulled = 1000 m
constant acceleration = 0.2 m/s²
Work done by the camper = ?
actual acceleration acting a'
m a = m a' - μ mg
a' = a + μ g
a' = 0.2 + 0.05 x 9.8
a' = 0.69 m/s²
Work done = Force x distance
F = m a'
F = 422.44897 N
Work done = F x d
Work done = 422.44897 x 1000
Work done = 422449 J
Work done = 422.45 kJ
Answer:
x₂=0.44m
Explanation:
First, we calculate the length the spring is stretch when the first block is hung from it:
Now, since the stretched spring is in equilibrium, we have that the spring restoring force must be equal to the weight of the block:
Solving for the spring constant k, we get:
Next, we use the same relationship, but for the second block, to find the value of the stretched length:
Finally, we sum this to the unstretched length to obtain the length of the spring:
In words, the length of the spring when the second block is hung from it, is 0.44m.