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3 years ago

The blackbody curve for a star named Zeta is shown below. What is the peak wavelength for this star?

Physics

2 answers:

VladimirAG [237]3 years ago

8 0

860 nanometers.

Hope this helps.

hram777 [196]3 years ago

3 0

Answer:

The answer is 860 nm!

Just took the test

Explanation:

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Which energy is cuased by an objects vibration

amm1812

D. sound energy........

3 0

2 years ago

Read 2 more answers

The gauge pressure in the tires of your car is 210 kPa (30.5 psi) when the temperature is 25°C (77 °F). Several days later it is

DaniilM [7]

Under the assumption that the tires do not change in volume, apply Gay-Lussac's law:

P/T = const.

P = pressure, T = temperature, the quotient of P/T must stay constant.

Initial P and T values:

P = 210kPa + 101.325kPa

P = 311.325kPa (add 101.325 to change gauge pressure to absolute pressure)

T = 25°C = 298.15K

Final P and T values:

P = ?, T = 0°C = 273.15K

Set the initial and final P/T values equal to each other and solve for the final P:

311.325/298.15 = P/273.15

P = 285.220kPa

Subtract 101.325kPa to find the final gauge pressure:

285.220kPa - 101.325kPa = 183.895271kPa

The final gauge pressure is 184kPa or 26.7psi.

8 0

3 years ago

Calculate the acceleration of a turtle going from 0.3 m/s to 0.7 m/s in 30 seconds.

Hoochie [10]

Acceleration = velocity/ time
Acceleration = 0.7-0.3 /30= 0.01 m/s^2
Notice that velocity is calculated the final speed minus the initial !

6 0

2 years ago

Em um centro de distribuição uma empilhadeira carrega uma caixa de 1000kg até o caminhão responsável pelo transporte desta carga

Yakvenalex [24]

Answer:

F = 592238.09 N

Explanation:

To find the mean force you first calculate the acceleration by using the following kinematic equation:

$v^2=v_o^2+2ax\\\\v_o=0m/s\\\\v=10km/h\\\\x=8.4m\\\\$

you do "a" the subject of the equation and replace the values of the other parameters:

$a=\frac{v^2}{2x}=\frac{10000m/s}{2(8.4m)}=595.23\frac{m}{s^2}$

next, the force, by using the second Newton law is:

$F=ma=(1000kg)(595.23\frac{m}{s^2})=595238.09\ N$

hence, the force is 592238.09 N

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TRANSLATION:

Para encontrar a força média, primeiro calcule a aceleração usando a seguinte equação cinemática:

você faz "a" o assunto da equação e substitui os valores dos outros parâmetros:

Em seguida, a força, usando a segunda lei de Newton, é:

portanto, a força é 592238.09 N

8 0

2 years ago

A certain parallel-plate capacitor is filled with a dielectric for which κ = 6.56. The area of each plate is 0.0830 m2, and the

mafiozo [28]

Answer:

$4.86\times 10^{-7}\ J$

Explanation:

Given:

Dielectric of the medium between the plates (k) = 6.56

Area of eac plate (A) = 0.0830 m²

Separation between the plates (d) = 1.95 mm = 0.00195 m [1 mm = 0.001 m]

Maximum electric field $(E_{max})$ = 202 kN/C = 202000 N/C [1 kN = 1000 N]

Permittivity of space (ε₀) = 8.854 × 10⁻¹² F/m

The maximum potential difference across the plates of the capacitor is given as:

$V_{max}=E_{max}d\\\\V=(202000\ N/C)(0.00195\ m)\\\\V=393.9\ V$

Now, capacitance of the capacitor is given as:

$C=\dfrac{k\epsilon_0A}{d}\\\\C=\frac{6.56\times 8.854\times 10^{-12}\ F/m\times 0.0830\ m^2}{0.00195\ m}\\\\C=2.47\times 10^{-9}\ F$

The maximum energy stored in the capacitor is given as:

$U_{max}=\frac{1}{2}CV_{max}^2\\\\U_{max}=\frac{1}{2}\times (2.47\times 10^{-9}\ F)\times 393.9\ V\\\\U_{max}=4.86\times 10^{-7}\ J$

Therefore, the maximum energy that can be stored in the capacitor is $4.86\times 10^{-7}\ J$

6 0

2 years ago