Answer:
The concentration of this sodiumhydroxide solutions is 0.50 M
Explanation:
Step 1: Data given
Mass of sodium hydroxide (NaOh) = 8.0 grams
Molar mass of sodium hydroxide = 40.0 g/mol
Volume water = 400 mL = 0.400 L
Step 2: Calculate moles NaOH
Moles NaOH = mass NaOH / molar mass NaOH
Moles NaOH = 8.0 grams / 40.0 g/mol
Moles NaOh = 0.20 moles
Step 3: Calculate concentration of the solution
Concentration solution = moles NaOH / volume water
Concentration solution = 0.20 moles / 0.400 L
Concentration solution = 0.50 M
The concentration of this sodiumhydroxide solutions is 0.50 M
Answer:
92gm
Explanation:
Atomic mass of Mg=24g=1 mole of Mg
∴ 24g =1 mole of Mg contain 6.022×10^23 atom
∴ 6gm contains 246.022×1023×6
=4×6.022×10^23 atoms
Now according to question, there are 6.022×1023 atoms of Na
23gm of Na contains 6.022×10^23 atoms
∴6.022×4×10^23 atoms of Na weighs 23×6.022×10^23×4/6.022×10^23⇒92gm
Answer:
<h3>it is important to carefully examine chemical reactions because there are many ways substances can be <em><u>reacting</u></em> without a chemical reaction taking place.</h3>
The atomic mass is defined as the mass an atom of an element. The atomic mass in approximation is equal to the sum of number of neutrons and protons in the nucleus of an atom (mass number). The units which are used for measuring the atomic mass is atomic mass unit,
.
Thus, the correct option is option E that is atomic mass unit is used for measuring atomic mass.
Answer:
The answer to your question is Pressure = 3.55 atm
Explanation:
Data
R = 0.082 atm L/mol°K
mass = 4.5 g
volume = 2 L
temperature = 35°C
Pressure = ?
Process
1.- Calculate the moles of Methane
molar weight = 12 + 4 = 16 g
16 g of Methane --------------- 1 mol
4.5 g --------------- x
x = (4.5 x 1)/16
x = 0.281 moles
2.- Convert temperature to Kelvin
°K = 273 + 35
= 308
3.- Use the ideal gas law to solve this problem
PV = nRT
- Solve for P
P = nRT / V
- Substitution
P = (0.281)(0.082)(308) / 2
- Simplification
P = 7.097 / 2
- Result
P = 3.55 atm