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sp2606 [1]
4 years ago
12

What is the standard form for 25x²+4y²+50x-24y-39=0

Mathematics
2 answers:
Thepotemich [5.8K]4 years ago
8 0
25x² + 4y² + 50x - 24y - 39 = 0
25x² + 50x + 4y² - 24y - 39 = 0
25x² + 50x - 39 = 0                                                      4y² - 24y - 39 = 0
x = <u>-b + √b² - 4ac</u>                                                        y<u> </u>= <u>-b + √b² - 4ac</u>
              2a                                                                              2a
x = <u>-50 + √(-50)² - 4(25)(-39)</u>                                        y =<u> -(-24) + √-(-24)² - 4(4)(-39)</u>
                 2(25)                                                                              2(4)
x = <u>-50 + √2500 + 3900</u>                                                y = <u>24 + √-576 + 624</u>
                   50                                                                                  8
x = <u>-50 + √6400</u>                                                            y =<u> 24 + √48
</u>            50                                                                                   8
x = <u>-50 + 80 </u>                                                                 y =<u> 24 + √16 × 3</u>
           50                                                                                          8
x = <u>-50 + 80</u>                                                                  y = <u>24 + √16 √3
</u>           50<u> </u>                                                                                    8     <u>
</u>x<u> </u>= -<u>50 + 80  </u>                                                               y = <u>24 + 4 √3</u>
           50                                                                                  8  
x = <u>-50 + 80</u><u> </u>                         <u />                                       y = <u>24 + 4 √3 </u>
           50                                                                                   8
x =<u> -50 + 80</u>   x = <u>-50 - 80</u>                                            y = <u>24 + 4 √3</u>     y = <u>24 - 4 √3</u>
          50                  50                                                              8                          8
x = <u>30</u>            x = -<u>130</u>                                                  y = <u>28 √3</u>            y = <u>20 √3</u>
      50                    50                                                              8                         8
x = <u>3</u>              x = <u>-13</u>                                                  y = <u>28 √3</u>               y = <u>20 √3</u>
      5                      5                                                             8                            8
 (x, y) = (<u>3</u>, <u>26 √3</u>)                                                        (x, y) = (<u>-13</u>, <u>20 √3 </u>)
              5     8                                                                            5      8
Korvikt [17]4 years ago
5 0
25x^2+4y^2+50x-24y-39=0\\&#10;25x^2+50x+25+4y^2-24y+36-100=0\\&#10;(5x+5)^2+(2y-6)^2=100
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