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3 years ago

10

andrew made a scale drawing of the elementary school. The scale of the drawing was 8 centimeters : 3 meters. if the actual lengt

h of the schoolyard is 30 meters, How long is the schoolyard in the drawing ?how long is the schoolyard in the drawing

1 answer:

Schach [20]3 years ago

4 0

Answer:i think its 80 cm

Step-by-step explanation:

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La finca de Federico tiene tiene un área de 576 m2, En ella ha sembrado naranja y café, 3/8 de la finca están sembrados de naran

Vanyuwa [196]

Answer:

El área de la finca que está sembrada por café es 360 m².

Step-by-step explanation:

La finca de Federico tiene tiene un área de 576 m². $\frac{3}{8}$ de la finca están sembrados de naranjas. Entonces, el área de la finca que está sembrada por naranjas se calcula mediante:

576 m²* $\frac{3}{8}$ = 216 m²

Sabiendo que el resto de la finca esta sembrada de café, esta área se calcula mediante la diferencia del área total de la finca y el área sembrada por naranjas:

576 m² - 216 m²= 360 m²

<u><em>El área de la finca que está sembrada por café es 360 m².</em></u>

6 0

3 years ago

Jason earns &10.59 per hour. He works 5.75 hours Saturday how much money does he earn Saturday? I know the answer is $60.89

marin [14]

So you are rounding 60.89.
I don't know which way you are aiming for to round, but here are some possible answers.
61.00
60.90
61.90

4 0

3 years ago

HELPP!!what is the answer to this picture above^

nasty-shy [4]

Answer:

$\fbox{ \fbox { \sf{Distance = \sf{15 \: units}}}}$

${ \fbox { \fbox { \sf{Midpoint = { \sf{ \: (12 \: , \: 10.5)}}}}}}$

Step-by-step explanation:

$\star{ \: \sf { \: Let \: the \: points \: be \: A \: and \: B}}$

$\star { \sf{Let \: A(6 \:, 6) \: be \: (x1 ,\: y1) \: and \: B(18 ,\: 15) \: be \: (x2 \:, y2)}}$

$\underline{ \underline{ \tt{Finding \: the \: distance}}}$

$\boxed{ \sf{Distance = \sqrt{ {(x2 - x1)}^{2} + {(y2 - y1)}^{2} } }}$

$\mapsto{ \sf{Distance = \sqrt{ {(18 - 6)}^{2} + {(15 - 6)}^{2} } }}$

$\mapsto{ \sf{Distance = \sqrt{ {(12)}^{2} + {(9)}^{2} } }}$

$\mapsto{ \sf{Distance = \sqrt{144 + 81}}}$

$\mapsto{ \sf{Distance = \sqrt{225} }}$

$\mapsto{ \sf{Distance = \sqrt{ {15}^{2} } }}$

$\mapsto{ \boxed{\sf{Distance = 15 \: units}}}$

$\underline{ \underline {\tt{Finding \: the \: Midpoint}}}$

$\boxed{ \sf{Midpoint = ( \frac{x1 + x2}{2} \: , \: \frac{y1 + y2}{2} )}}$

$\mapsto{ \sf{Midpoint = ( \frac{6 + 18}{2} \: , \: \frac{6 + 15}{2} )}}$

$\mapsto{ \sf{Midpoint = ( \frac{24}{2} \: , \: \frac{21}{2} )}}$

$\mapsto{ \boxed{ \sf{Midpoint = (12 \: , \: 10.5)}}}$

Hope I helped!

Best regards! :D

~ $\sf{TheAnimeGirl}$

3 0

2 years ago

What is 7 + 8(2r - 9)

Shalnov [3]

7 + 8(2r - 9)

mutiply the bracket by 8

(8)(2r)= 16r

(8)(-9)= -72

7+16r-72

7-72+16r ( rearranging)

answer:

-65+16r or 16r-65

4 0

3 years ago

Read 2 more answers

I need help please list all the available factors. PLEASE

lara [203]

Thing I no this one I just forgot

3 0

2 years ago