CH₃ CH 2 CH 2 OH to form an unsaturated compound using the reagent of h2so4
1 answer:
Propene is the unsaturated compound.
Explanation:
In the presence of sulphuric acid (H₂SO₄), propanol will eliminate one water molecule (H₂O) to form propene, which is the unsaturated compound.
You may find the chemical reaction with the chemical diagrams of the compounds in the attached picture.
Learn more about:
dehydration of alcohols
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Answer:
0.124 mol Ag
General Formulas and Concepts:
<u>Atomic Structure</u>
- Moles
<u>Stoichiometry</u>
- Using Dimensional Analysis
Explanation:
<u>Step 1: Define</u>
[Given] 7.49 × 10²² atoms Ag
[Solve] mol Ag
<u>Step 2: Identify Conversions</u>
Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<u>Step 3: Convert</u>
- [DA] Set up:
- [DA] Divide [Cancel out units]:
<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 3 sig figs.</em>
0.124377 mol Ag ≈ 0.124 mol Ag
Topic: AP Chemistry
<u>Answer:</u> The mass of gallium produced by the electrolysis is 0.0354 grams.
<u>Explanation:</u>
The equation for the deposition of Ga(s) from Ga(III) solution follows:
- To calculate the total charge, we use the equation:
where,
C = charge
I = current = 0.490 A
t = time required (in seconds) = (Conversion factor: 1 min = 60 s)
Putting values in above equation, we get:
- To calculate the moles of electrons, we use the equation:
where,
C = charge = 147 C
F = Faradays constant = 96500
- Now, to calculate the moles of gallium, we use the equation:
where,
n = number of electrons transferred = 3
Putting values in above equation, we get:
- To calculate the mass of gallium, we use the equation:
Moles of Gallium =
Molar mass of Gallium = 69.72 g/mol
Putting values in above equation, we get:
Hence, the mass of gallium produced by the electrolysis is 0.0354 grams.