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babunello [35]
3 years ago
5

Which is a metal alloy?

Chemistry
2 answers:
Mumz [18]3 years ago
3 0

Answer:

C

Explanation:

Steel is an alloy of iron and carbon.

Reil [10]3 years ago
3 0
I believe its copper
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Radiation is spontaneously emitted from hydrogen-3 nuclei, but radiation is not spontaneously emitted from hydrogen-l nuclei or
miv72 [106K]

Answer : Option 1) nuclei of H^{1} and nuclei of H^{2} only.


Explanation : Radiation is spontaneously emitted from nuclei of H^{3} because this isotope of hydrogen is highly radioactive as compared to other isotopes of hydrogen namely; nuclei of H^{1} and nuclei of H^{2}.


They have much stable nucleus as compared to nuclei of H^{3}.


The more it is unstable the more radiations will be emitted from its nucleus.

5 0
3 years ago
Read 2 more answers
Sodium is a larger atom than lithium. List three reasons why this is true.
just olya [345]

Answer:

It is present in third period that's why its valance electrons are present in 3rd energy level.

Its atomic number is greater than lithium when compared in group wise.

There are more electrons in sodium to shield the outer valance electron thus nuclear attraction becomes weak and size increase.

Explanation:

The size of sodium is greater than lithium because atomic number of sodium is 11 and lithium is 3. Both are present in first group but sodium is present down to the lithium. As we move from top to bottom in a group atomic size increases with addition of electrons. The nuclear effect become weaker on valance electrons and atomic size increase. Same time shielding effect is also produces which shield the outer electrons from the influence of nucleus. While in case of lithium less electrons are present to shield the valance electrons.

As we note the position of both elements along period. The sodium is present in third period while lithium is present in second period. So, in case of sodium third energy level is involved. That's why its size is greater than lithium.

8 0
3 years ago
The CO 2-ion is stabilized by (A resonance. B inductive effects. c heterolysis. D potential energy.
FromTheMoon [43]

Answer: Option (A) is the correct answer.

Explanation:

A phenomenon where delocalization of pi electrons or non-bonding electrons takes place is known as resonance.

For example, in a CO^{2-}_{3} molecule two oxygen atoms contain -1 charge. And, delocalization of pi electrons takes place in order to attain stability.

When in a molecule, there occurs unequal sharing of bonding electrons by a chain of atoms then there occurs a permanent dipole moment. And, this effect is known as inductive effect.

So, basically more difference in electronegativity of the atoms in a molecule tend to cause inductive effect.

In CO^{2-}_{3}, there is not much difference in the electronegativity of carbon and oxygen atom.

Hence, resonance effect predominates inductive effect.

Potential energy is the energy obtained by an object due to its position.

Thus, we can conclude that the CO^{2-}_{3} ion is stabilized by resonance.

4 0
3 years ago
What percentage of energy used in the u.s is produced from fossil fuels
wel

Fossil Fuels Account for Lowest Share of U.S. Energy Consumption in More than a Century. Fossil fuels supplied about 80 percent of the energy consumed in the United States in 2017, the lowest share since 1902, according to a new report from the U.S. Department of Energy.

5 0
4 years ago
Please Help! Use Hess’s Law to determine the ΔHrxn for: Ca (s) + ½ O2 (g) → CaO (s) Given: Ca (s) + 2 H+ (aq) → Ca2+ (aq) + H2 (
poizon [28]

Answer:

ΔHrxn = -635.14kJ/mol

Explanation:

We can make algebraic operations of reactions until obtain the desire reaction and, ΔH of the reaction must be operated in the same way to obtain the ΔH of the desire reaction (Hess's law). Using the reactions:

(1)Ca(s) + 2 H+(aq) → Ca2+(aq) + H2(g) ΔH = 1925.9 kJ/mol

(2) 2H2(g) + O2 g) → 2 H2O(l) ΔH = −571.68 kJ/mole

(3) CaO(s) + 2 H+(aq) → Ca2+(aq) + H2O(l) ΔH = 2275.2 kJ/mole

Reaction (1) - (3) produce:

Ca(s) + H2O(l) → H2(g) + CaO(s)

ΔH = 1925.9kJ/mol - 2275.2kJ/mol = -349.3kJ/mol

Now this reaction + 1/2(2):

Ca(s) + ½ O2(g) → CaO(s)

ΔH = -349.3kJ/mol + 1/2 (-571.68kJ/mol)

<h3>ΔHrxn = -635.14kJ/mol</h3>
7 0
3 years ago
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