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3 years ago

Which of the following happens when chlorine forms an ion?

Chemistry

2 answers:

Jlenok [28]3 years ago

7 0

What happens when chlorine form an ion is that it gains an electron and has an octet in its outer shell ( answer A)

Explanation

Chlorine is is in atomic number 17 in periodic table.

The electron configuration of chlorine is 1S2 2S2 2P6 3S2 3P5 or[Ne]3S2 3p5 or 2.8.7.

chlorine therefore has 7 valence electron therefore it gain 1 electron to form Cl- ( ion)

Cl- has 8 electron in its outer shell ( it obeys octet rule of eight valence in outer shell.

kotykmax [81]3 years ago

7 0

When chlorine forms an ion it gains an electron and has an octet in its outer shell. The correct answer is A.

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3 years ago

Read 2 more answers

A gas stp is 4.38 L how many moles are there ?

kaheart [24]

Answer:

There are 0.195 moles.

Explanation:

1 mol of any gas under STP (meaning 1 atm and 273 K) will occupy 22.4 liters.

With the information above in mind, we can calculate how many moles will occupy 4.38 liters:

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2 years ago

Two identical containers, one red and one yellow, are inflated with different gases at the same volume and pressure. Both contai

Evgen [1.6K]

Answer:

Explanation:

Here we're dealing with the root mean square velocity of gases. We'll provide the formula in order to calculate the root mean square velocity of a gas:

$v_{rms}=\sqrt{\frac{3RT}{M}}$

Here:

$R = 8.314 \frac{J}{K mol}$ is the ideal gas law constant;

$T$ is the absolute temperature in K;

$M$ is the molar mass of a compound in kg/mol.

We know that the gas from the red container is 4 times faster, as it takes 4 times as long for the yellow container to leak out, this means:

$\frac{v_{rms, red}}{v_{rms, yellow}} = 4$

We also know that the temperature of the red container is twice as large:

$\frac{T_{red}}{T_{yellow}} = 2$

Write the ratio of the velocities and substitute the variables:

$\frac{v_{rms, red}}{v_{rms, yellow}}=\frac{\sqrt{\frac{3RT_{red}}{M_{red}}}}{\sqrt{\frac{3RT_{yellow}}{M_{yellow}}}}=4$

Then:

$\frac{\sqrt{\frac{3RT_{red}}{M_{red}}}}{\sqrt{\frac{3RT_{yellow}}{M_{yellow}}}}=\sqrt{\frac{3RT_{red}}{M_{red}}\cdot \frac{M_{yellow}}{3RT_{yellow}}}=\sqrt{\frac{T_{red}}{T_{yellow}}\cdot \frac{M_{yellow}}{M_{red}}}=4$