It is 50. This is because heat goes from higher temperatures to lower and nothing else in the options is lower.
A). 4
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Answer:
Explanation:
A 30.0g sample of O2 at standard temperature and pressure (STP) would occupy what volume in liters
PV =nRT
at STP P= 1atm. T= 273 K
n is the number of moles. O2 has a molar mass of 32.
30 gm of O2 is 30/32= 0.94 =n
PV = nRT
at STP: P= 1 atm, T=273 K, R is always 0.082 for P in atm and T in K
SO
1 X V = 0.94 X 0.082 X 273
using high school freshman algebra,
V= 0.94 X 0.082 X 273 = 21L
using high school algebra I,
V=
KClO3 (aq) will have greater molar entropy than KClO3 (s) because molar entropy increases with increase in temperature.
As the temperature rises, the standard molar entropy of any substance rises. Entropy and a Single Substance's Temperature ” Entropy increases significantly when a solid turns into a liquid and when a liquid turns into a gas. The entropy of the liquid is lower than that of the gas. As a result, entropy rises in reactions that produce gaseous byproducts from solid or liquid reactants. When solid reactants produce liquid products, entropy also rises.
Learn more about Molar entropy here-
brainly.com/question/3627396
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