All categories

3 years ago

What is the mechanical advantage supplied by a 1000 N object lifted using 250 N of force

Physics

1 answer:

Ivenika [448]3 years ago

4 0

Answer:

Mechanical advantage=4

Explanation:

Load=1000N

Effort=250N

mechanical advantage=load/effort

Mechanical advantage=1000/250

Mechanical advantage=4

You might be interested in

If revenue is $3,000 and operating expenses are $4,000, cash flow equals _____. -$1,000 $1,000 -$7,000 $7,000

valkas [14]

Answer:

-$1,000

Explanation:

$3000 - $4000

4 0

3 years ago

Which material will displace a volume of water? Which material will displace a volume of water less than its own volume? Which m

horrorfan [7]

Answer:

1. all of them

2. cork and wax

3. iron, lead, and aluminum

4. none of them

Explanation:

1.Which material will displace a volume of water? all of them

When an object is introduced into a container with a volume of water, a volume of liquid equal to the volume of the object is displaced

2.Which material will displace a volume of water less than its own volume?

cork and wax

because the density of the object is less than that of the displaced liquid

3.Which material will displace a volume of water equal to its own volume?

iron, lead, and aluminum

because Arquimedes's principle: any body plunged inside a fluid in this case water experiences an ascending force called push, equivalent to the weight of the fluid removed by the body

4.Which material will displace a volume of water greater than its own volume?

None of them

7 0

2 years ago

How could a food web based in water be connected to a food web based on land? Give an example.

Serggg [28]

Land animals could eat water animals For example, a bear could eat salmon from the river and that could be connected to organisms from water to land

4 0

3 years ago

Read 2 more answers

In 1993, the gold reserves in the United States were about 8.490 x 10^6

lorasvet [3.4K]

Mass of gold :-8.490×10⁶kg
Density=19300kg/m³

Volume?

Let's see

Volume:-

Mass/Density
8.49×10⁶/19300
0.000439×10⁶
439m³

6 0

2 years ago

Suppose you have a 0.750-kg object on a horizontal surface connected to a spring that has a force constant of 150 N/m. There is

marshall27 [118]

Answer:

$x=0.0049\ m= 4.9\ mm$

$d=0.01153\ m=11.53\ mm$

Explanation:

Given:

mass of the object, $m=0.75\ kg$

elastic constant of the connected spring, $k=150\ N.m^{-1}$

coefficient of static friction between the object and the surface, $\mu_s=0.1$

(a)

Let x be the maximum distance of stretch without moving the mass.

The spring can be stretched up to the limiting frictional force 'f' till the body is stationary.

$f=k.x$

$\mu_s.N=k.x$

where:

N = m.g = the normal reaction force acting on the body under steady state.

$0.1\times (9.8\times 0.75)=150\times x$

$x=0.0049\ m= 4.9\ mm$

(b)

Now, according to the question:

Amplitude of oscillation, $A= 0.0098\ m$

coefficient of kinetic friction between the object and the surface, $\mu_k=0.085$

Let d be the total distance the object travels before stopping.

Now, the energy stored in the spring due to vibration of amplitude:

$U=\frac{1}{2} k.A^2$

This energy will be equal to the work done by the kinetic friction to stop it.

$U=F_k.d$

$\frac{1}{2} k.A^2=\mu_k.N.d$

$0.5\times 150\times 0.0098^2=0.0850 \times 0.75\times 9.8\times d$

$d=0.01153\ m=11.53\ mm$

is the total distance does it travel before stopping.

7 0

2 years ago